# Pythagorea Parallels Level 2.16 Solution/Answer

Pythagorea Parallels Level 2.16 New Version Game Answers, detailed solutions, Tips, and Walkthrough. Scroll below to find answer to this level.

Pythagorea is android/iOS app developed by Horis International Limited. Solutions hints and answers to pythagorea are available in this post scroll down to find solutions to all the levels.

This game is mostly focused on geometric puzzles and construction. The workspace is divided into grids to draw lines. You should know all the basic Math operations. All lines and shapes are drawn on a grid whose cells are squares. Most of the game levels can be answered using natural intuition and by some basic laws of geometry.

Click Here for All other Pythagorea Levels: http://www.puzzlegamemaster.com/pythagorea/

**Pythagorea parallels 2.16:** Construct a line through the point A that is parallel to the given line.

If you have any doubt regarding Pythagorea answers given here you can watch video below or you can comment on this post-

Not-so-elegant solution using x-y equations:

1. Use (0,0) at the bottom left as the reference point for representing the entire 6 x 6 grid as an x,y coordinate plane. Given that as what is established, the given line would be represented by

y = (3/5)x.

2. Since point A is at (2,4), find y at the given line when x = 2, which is 6/5. Find the difference in y-coordinates between point A and (2, 6/5): 4 – 6/5 = 20/5 – 6/5 = 14/5. This gives you the y-translation to find the second equation that intersects point A: y = (3/5)x + 14/5

3. Pick an (x, y) value within the visible 6 x 6 grid for your newly found equation. I’m going to choose x = 4, which will give you y = (26/5).

4.

The not-so-elegant part:

Find and draw a line segment that will hit (4, 26/5). This line segment will have to have a slope that will go a fifth of a y-unit up whenever the x-value traverses 1 unit left or right. The line segment will be up to your choosing. I chose the one between (5,5) and (0,6).

5. Draw the line between point A and (4, 26/5).

Perfect! Thanks a lot.

From the original triangle:

5/3=3/x then x=9/5

From your triangle:

5/4=1/y then y=4/5

So, y+1=4/5 + 5/5=x

Very smart! Congratulations.

what about this ? http://tinypic.com/r/23ua63q/9

You might have had to use math. Just saying.

Think of it like this: the slope is 3/5 so you can expect the y value at x=5 (if the origin is the bottom left) to be 4 + (3/5)*3 = 5 + 4/5 = 6 – 1/5. In order to make a point at (5, 6 – 1/5), construct a line with a slope of 1/5 so that for each x you travel left, the value decreases by 1/5. As long as this line intersects (6, 6), it will intersect (5, 6 – 1/5) also. This approach also works if you make the endpoints of the secondary line at (0,4) and (5,5). The paralell line will intersect the secondary line at (3, 4 + 3/5).

Every 3 along, the line goes up 1.8 (gradient 3/5). The construction line allows the square grid to be split into fifths vertically. So from A, 3 along and 1.8 up is where the construction point has gone, keeping gradient same as original. Ok?

Just because your “solution” is correct doesn’t mean you used math to get it. Your choice of line to get the second point on the parallel line seems chosen at random.

The original line goes along 3 and up 9/5 (gradient of 3/5). The construction line allows the vertical distances to be split into fifths, so the constructed point is 3 along and 9/5 up from point A, allowing lines to be parallel.

I too don’t see any math involved in this solution.

Every 3 along, the line goes up 1.8 (gradient 5/3). The construction line allows the square grid to be split into fifths vertically. So from A, 3 along and 1.8 up is where the construction point has gone, keeping gradient same as original. Ok?

Went to link. Looked at the drawing. Line AF does not have a 5/3 slope. Line BC does. How can they be parallel?

2.16 “solution” is incorrect. It is not based on any math, and you can see that the vertcal distance between point A and the line and another point on the new line to the original line is different.

https://imgur.com/TGh8b0X

Go to this link to find out why it is correct, I tried online simulator to check.

Yep, I don’t get how the provided solution is correct. AF line has a slope of -8/5 and the CB line has a slope of -5/3 They will intersect.

here you can see how both lines have slope +3/5: https://imgur.com/a/B1ji9

and scroll to see that they will not intersect if I zoom out (here are two images)

Ok zoomed in you can see that the line AF has the correct slope. What did you base the line DE on?