Everyday Grids Zip Answer Today: July 22, 2025

This page has the complete Everyday Grids Zip answers for July 22, 2025 (22 July 2025): the solved grids for both the Normal and Hard Zip levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Zip guide? It’s all below, and each Everyday Grids Zip solution is verified against the puzzle rules, so it matches the Jul 22, 2025 puzzle in the app exactly.
About Everyday Grids Zip
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Zip is one of them. Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can’t cross walls. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Zip puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Zip Answers and Solutions for July 22, 2025
Each level below shows the solved Zip grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Zip Normal Answer, Jul 22, 2025
6×6 grid- 0/48Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 48 logical steps, no guessing.
- 1/48R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/48R1C6 needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 3/48R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 4/48R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 5/48Seed 11 (R4C1) needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 6/48R4C2 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 7/48R5C6 needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 8/48As the start, seed 1 (R6C6) needs exactly one connection. Closed sides, down/right: edge of the board; up: wall. So the path must go left from here.
- 9/48Check: if the path did NOT use the link R1C3–R1C4, then after 1 forced move the numbers 11→10→3 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 10/48Check: if the path did NOT use the link R2C2–R3C2, then after 1 forced move the numbers 11→10→3 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 11/48R3C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 12/48Check: if the path did NOT use the link R3C3–R3C4, then after 1 forced move the numbers 3→5 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 13/48Check: if the path used the link R3C4–R3C5, then after 3 forced moves the numbers 5→8 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 14/48Check: if the path used the link R5C2–R5C3, then after 3 forced moves R6C2 would become a dead end (not enough ways in and out). (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 15/48Check: if the path did NOT use the link R6C2–R6C3, then after 3 forced moves R5C1 would become a dead end (not enough ways in and out). (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 16/48Check: if the path did NOT use the link R6C4–R6C5, then after 3 forced moves the numbers 5→6→2 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 17/48R6C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 18/48Check: if the path did NOT use the link R4C3–R5C3, then after 5 forced moves the numbers 6→2→1 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 19/48Check: if the path used the link R5C1–R5C2, then after 7 forced moves the numbers 3→11→10 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 20/48R5C1 needs two connections (in and out). Closed sides, left: edge of the board; right: leads to a contradiction. So the path must go up and down from here.
- 21/48Dot 12 at R6C1 already has its one connection, it is the finish of the path, so the path cannot use its other side(s). Mark them as closed.
- 22/48R5C2 needs two connections (in and out). Closed sides, left: leads to a contradiction, right: leads to a contradiction. So the path must go up and down from here.
- 23/48Check: if the path did NOT use the link R5C3–R5C4, then after 7 forced moves the numbers 5→6→3 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 24/48Dot 6 at R5C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 25/48R6C3 needs two connections (in and out). Closed sides, down: edge of the board; up: R5C3 already has its two connections. So the path must go left and right from here.
- 26/48Dot 2 at R6C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 27/48Linking R1C2 and R2C2 is impossible: it would put the numbers in the order 12→11→10→2→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 28/48Seed 10 (R1C2) needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 12→11→10→2→1 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 29/48R1C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 30/48R2C2 needs two connections (in and out). Closed sides, up: it would put the numbers in the order 12→11→10→2→1 on one stretch of path, but they must be visited in sequence, left: wall. So the path must go right and down from here.
- 31/48Linking R1C4 and R2C4 is impossible: it would put the numbers in the order 12→11→10→4 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 32/48R1C4 needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 12→11→10→4 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 33/48R1C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 34/48Check: if the path did NOT use the link R2C5–R2C6, then after 1 forced move the numbers 4→8 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 35/48Dot 9 at R2C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 36/48R3C6 needs two connections (in and out). Closed sides, right: edge of the board; up: R2C6 already has its two connections. So the path must go left and down from here.
- 37/48R4C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 38/48Linking R2C4 and R2C5 is impossible: it would put the numbers in the order 4→9→10→11→12 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 39/48Seed 4 (R2C4) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 12→11→10→4 on one stretch of path, but they must be visited in sequence, right: it would put the numbers in the order 4→9→10→11→12 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 40/48Dot 3 at R2C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 41/48R3C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 42/48R2C5 needs two connections (in and out). Closed sides, up: R1C5 already has its two connections, left: it would put the numbers in the order 4→9→10→11→12 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 43/48Dot 8 at R3C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 44/48R3C3 needs two connections (in and out). Closed sides, up: R2C3 already has its two connections, left: R3C2 already has its two connections. So the path must go right and down from here.
- 45/48Dot 5 at R4C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 46/48R4C4 needs two connections (in and out). Closed sides, up: R3C4 already has its two connections, left: R4C3 already has its two connections. So the path must go right and down from here.
- 47/48R5C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 48/48Seed 7 (R4C5) needs two connections (in and out). Closed sides, up: R3C5 already has its two connections, right: R4C6 already has its two connections. So the path must go left and down from here. ✅ Solved!
Zip Normal answer as text
Everyday Grids Zip Hard Answer, Jul 22, 2025
6×6 grid- 0/34Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 34 logical steps, no guessing.
- 1/34R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/34R1C2 needs two connections (in and out). Closed sides, up: edge of the board; right: wall. So the path must go left and down from here.
- 3/34Dot 6 at R2C2 already has its one connection, it is the finish of the path, so the path cannot use its other side(s). Mark them as closed.
- 4/34R1C3 needs two connections (in and out). Closed sides, up: edge of the board; left: wall. So the path must go right and down from here.
- 5/34R1C6 needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 6/34R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: R2C2 already has its single connection (it is an end of the path). So the path must go up and down from here.
- 7/34Seed 3 (R2C6) needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 8/34R3C4 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 9/34R3C6 needs two connections (in and out). Closed sides, right: edge of the board; up: wall. So the path must go left and down from here.
- 10/34R4C6 needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 11/34R5C3 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 12/34Seed 5 (R5C4) needs two connections (in and out). Closed sides, up: wall, right: wall. So the path must go left and down from here.
- 13/34R5C5 needs two connections (in and out). Closed sides, left: wall, down: wall. So the path must go up and right from here.
- 14/34R4C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 15/34R3C5 needs two connections (in and out). Closed sides, left: wall, down: R4C5 already has its two connections. So the path must go up and right from here.
- 16/34R2C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 17/34R1C5 needs two connections (in and out). Closed sides, up: edge of the board; down: R2C5 already has its two connections. So the path must go left and right from here.
- 18/34Dot 2 at R1C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 19/34R2C4 needs two connections (in and out). Closed sides, up: R1C4 already has its two connections, right: R2C5 already has its two connections. So the path must go left and down from here.
- 20/34R2C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 21/34R3C3 needs two connections (in and out). Closed sides, up: R2C3 already has its two connections, right: wall. So the path must go left and down from here.
- 22/34Dot 1 at R3C2 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 23/34R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: R3C2 already has its single connection (it is an end of the path). So the path must go up and down from here.
- 24/34R4C4 needs two connections (in and out). Closed sides, right: R4C5 already has its two connections, down: wall. So the path must go up and left from here.
- 25/34R4C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 26/34R4C2 needs two connections (in and out). Closed sides, up: R3C2 already has its single connection (it is an end of the path), right: R4C3 already has its two connections. So the path must go left and down from here.
- 27/34R4C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 28/34R5C1 needs two connections (in and out). Closed sides, left: edge of the board; up: R4C1 already has its two connections. So the path must go right and down from here.
- 29/34R5C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 30/34R5C6 needs two connections (in and out). Closed sides, right: edge of the board; up: wall. So the path must go left and down from here.
- 31/34R6C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 32/34R6C2 needs two connections (in and out). Closed sides, down: edge of the board; up: R5C2 already has its two connections. So the path must go left and right from here.
- 33/34R6C4 needs two connections (in and out). Closed sides, down: edge of the board; left: wall. So the path must go up and right from here.
- 34/34Seed 4 (R6C5) needs two connections (in and out). Closed sides, down: edge of the board; up: wall. So the path must go left and right from here. ✅ Solved!
Zip Hard answer as text
How to Solve Everyday Grids Zip: Quick Tips
- Start with cells that have only two open sides, the path is forced straight through them.
- Corners and dead-end pockets between walls must be entered and left immediately, so draw those links first.
- Never join two path pieces into a loop, and never connect numbers out of order.
- If a group of cells has only one way in, the path must use it, or that group would be left unvisited.