Everyday Grids Zip Answer Today: October 26, 2026

This page has the complete Everyday Grids Zip answers for October 26, 2026 (26 October 2026): the solved grids for both the Normal and Hard Zip levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Zip guide? It’s all below, and each Everyday Grids Zip solution is verified against the puzzle rules, so it matches the Oct 26, 2026 puzzle in the app exactly.
About Everyday Grids Zip
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Zip is one of them. Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can’t cross walls. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Zip puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Zip Answers and Solutions for October 26, 2026
Each level below shows the solved Zip grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Zip Normal Answer, Oct 26, 2026
5×5 grid- 0/30Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 30 logical steps, no guessing.
- 1/30R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/30R1C5 needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 3/30R3C5 needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 4/30Dot 5 at R2C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 5/30R5C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 6/30R5C3 needs two connections (in and out). Closed sides, down: edge of the board; right: wall. So the path must go up and left from here.
- 7/30R5C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 8/30Seed 6 (R5C4) needs two connections (in and out). Closed sides, down: edge of the board; left: wall. So the path must go up and right from here.
- 9/30R5C5 needs two connections (in and out). Closed sides, down/right: edge of the board. So the path must go up and left from here.
- 10/30R4C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 11/30Linking R1C4 and R2C4 is impossible: it would put the numbers in the order 6→5→7 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 12/30R1C4 needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 6→5→7 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 13/30Linking R3C2 and R4C2 is impossible: it would connect seed 4 straight to seed 1. Mark that side closed.
- 14/30Seed 4 (R3C2) needs two connections (in and out). Closed sides, right: wall, down: it would connect seed 4 straight to seed 1. So the path must go up and left from here.
- 15/30Linking R3C1 and R4C1 is impossible: it would put the numbers in the order 4→2→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 16/30R3C1 needs two connections (in and out). Closed sides, left: edge of the board; down: it would put the numbers in the order 4→2→3 on one stretch of path, but they must be visited in sequence. So the path must go up and right from here.
- 17/30R2C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 18/30Seed 2 (R4C1) needs two connections (in and out). Closed sides, left: edge of the board; up: it would put the numbers in the order 4→2→3 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 19/30Dot 1 at R4C2 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 20/30Linking R1C2 and R2C2 is impossible: it would close a loop. Mark that side closed.
- 21/30R1C2 needs two connections (in and out). Closed sides, up: edge of the board; down: it would close a loop. So the path must go left and right from here.
- 22/30R1C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 23/30R2C2 needs two connections (in and out). Closed sides, up: it would close a loop, left: R2C1 already has its two connections. So the path must go right and down from here.
- 24/30Linking R2C3 and R2C4 is impossible: it would put the numbers in the order 6→5→4→7 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 25/30R2C3 needs two connections (in and out). Closed sides, up: R1C3 already has its two connections, right: it would put the numbers in the order 6→5→4→7 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 26/30As the finish, seed 7 (R2C4) needs exactly one connection. Closed sides, up: it would put the numbers in the order 6→5→7 on one stretch of path, but they must be visited in sequence, left: it would put the numbers in the order 6→5→4→7 on one stretch of path, but they must be visited in sequence, right: R2C5 already has its two connections. So the path must go down from here.
- 27/30Linking R3C3 and R3C4 is impossible: it would put the numbers in the order 6→5→4→7 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 28/30R3C3 needs two connections (in and out). Closed sides, left: wall, right: it would put the numbers in the order 6→5→4→7 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 29/30Dot 3 at R4C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 30/30R3C4 needs two connections (in and out). Closed sides, left: it would put the numbers in the order 6→5→4→7 on one stretch of path, but they must be visited in sequence, right: wall. So the path must go up and down from here. ✅ Solved!
Zip Normal answer as text
Everyday Grids Zip Hard Answer, Oct 26, 2026
6×6 grid- 0/38Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 38 logical steps, no guessing.
- 1/38R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/38R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 3/38R2C3 needs two connections (in and out). Closed sides, right: wall, down: wall. So the path must go up and left from here.
- 4/38R4C2 needs two connections (in and out). Closed sides, up: wall, right: wall. So the path must go left and down from here.
- 5/38R4C3 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 6/38R4C4 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 7/38Seed 2 (R4C5) needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 8/38R6C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 9/38Seed 4 (R6C3) needs two connections (in and out). Closed sides, down: edge of the board; up: wall. So the path must go left and right from here.
- 10/38R6C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 11/38R6C4 needs two connections (in and out). Closed sides, down: edge of the board; up: wall. So the path must go left and right from here.
- 12/38R6C6 needs two connections (in and out). Closed sides, down/right: edge of the board. So the path must go up and left from here.
- 13/38Dot 3 at R6C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 14/38Linking R1C6 and R2C6 is impossible: it would connect seed 8 straight to seed 1. Mark that side closed.
- 15/38As the finish, seed 8 (R1C6) needs exactly one connection. Closed sides, up/right: edge of the board; down: it would connect seed 8 straight to seed 1. So the path must go left from here.
- 16/38Linking R1C4 and R1C5 is impossible: it would put the numbers in the order 6→8 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 17/38Seed 6 (R1C4) needs two connections (in and out). Closed sides, up: edge of the board; right: it would put the numbers in the order 6→8 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 18/38R1C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 19/38Seed 5 (R1C2) needs two connections (in and out). Closed sides, up: edge of the board; right: R1C3 already has its two connections. So the path must go left and down from here.
- 20/38R2C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 21/38R1C5 needs two connections (in and out). Closed sides, up: edge of the board; left: it would put the numbers in the order 6→8 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 22/38R3C2 needs two connections (in and out). Closed sides, up: R2C2 already has its two connections, down: wall. So the path must go left and right from here.
- 23/38R3C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 24/38R3C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 25/38R4C1 needs two connections (in and out). Closed sides, left: edge of the board; up: R3C1 already has its two connections. So the path must go right and down from here.
- 26/38R5C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 27/38R5C2 needs two connections (in and out). Closed sides, left: R5C1 already has its two connections, down: R6C2 already has its two connections. So the path must go up and right from here.
- 28/38R5C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 29/38R5C4 needs two connections (in and out). Closed sides, left: R5C3 already has its two connections, down: wall. So the path must go up and right from here.
- 30/38R5C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 31/38R5C6 needs two connections (in and out). Closed sides, right: edge of the board; left: R5C5 already has its two connections. So the path must go up and down from here.
- 32/38R4C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 33/38R3C6 needs two connections (in and out). Closed sides, right: edge of the board; down: R4C6 already has its two connections. So the path must go up and left from here.
- 34/38Dot 1 at R2C6 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 35/38Linking R2C4 and R3C4 is impossible: it would close a loop. Mark that side closed.
- 36/38R2C4 needs two connections (in and out). Closed sides, left: wall, down: it would close a loop. So the path must go up and right from here.
- 37/38Dot 7 at R2C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 38/38R3C4 needs two connections (in and out). Closed sides, up: it would close a loop, left: R3C3 already has its two connections. So the path must go right and down from here. ✅ Solved!
Zip Hard answer as text
How to Solve Everyday Grids Zip: Quick Tips
- Start with cells that have only two open sides, the path is forced straight through them.
- Corners and dead-end pockets between walls must be entered and left immediately, so draw those links first.
- Never join two path pieces into a loop, and never connect numbers out of order.
- If a group of cells has only one way in, the path must use it, or that group would be left unvisited.