Everyday Grids Sums Answer Today: October 22, 2026

This page has the complete Everyday Grids Sums answers for October 22, 2026 (22 October 2026): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Oct 22, 2026 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for October 22, 2026
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Oct 22, 2026
6×6 grid- 0/12Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 12 logical steps, no guessing.
- 1/12Column 3 must total 24 using 8, 5, 7, 4, 4, 3. The ways to make 24 are: 8+5+7+4, 8+5+4+4+3 (some using different copies of the same number). Every one uses R1C3, R2C3, so keep them.
- 2/12Peach area must total 17; the kept 8 = 8 so far, so the undecided numbers (5, 6, 6, 3) must add up to 9. The ways to make 9 are: 6+3 (some using different copies of the same number). Every one uses R2C1, so keep it; none uses R1C1, so remove it.
- 3/12Row 2 must total 23; the kept 3+5 = 8 so far, so the undecided numbers (9, 5, 7, 6) must add up to 15. The only way to make 15 is 9 + 6. So keep R2C2, R2C6; remove R2C4, R2C5.
- 4/12Brown area must total 17; the kept 9+5 = 14 so far, so the undecided numbers (3, 5) must add up to 3. The only way to make 3 is 3. So keep R3C1; remove R3C2.
- 5/12Row 3 must total 20; the kept 3 = 3 so far, so the undecided numbers (7, 8, 5, 4) must add up to 17. The only way to make 17 is 8 + 5 + 4. So keep R3C4, R3C5, R3C6; remove R3C3.
- 6/12Column 4 must total 11; the kept 8 = 8 so far, so the undecided numbers (6, 5, 7, 3) must add up to 3. The only way to make 3 is 3. So keep R6C4; remove R1C4, R4C4, R5C4.
- 7/12Green area must total 17 using 7, 1, 3, 9. The only way to make 17 is 7 + 1 + 9. So keep R4C5, R5C5, R6C6; remove R6C5.
- 8/12Row 1 must total 20; the kept 8 = 8 so far, so the undecided numbers (6, 3, 3) must add up to 12. The only way to make 12 is 6 + 3 + 3. So keep R1C2, R1C5, R1C6.
- 9/12Row 6 must total 21; the kept 3+9 = 12 so far, so the undecided numbers (3, 3, 3) must add up to 9. The only way to make 9 is 3 + 3 + 3. So keep R6C1, R6C2, R6C3.
- 10/12Column 2 must total 20; the kept 6+9+3 = 18 so far, so the undecided numbers (2, 6) must add up to 2. The only way to make 2 is 2. So keep R4C2; remove R5C2.
- 11/12Row 4 must total 13; the kept 2+7 = 9 so far, so the undecided numbers (6, 4, 9) must add up to 4. The only way to make 4 is 4. So keep R4C3; remove R4C1, R4C6.
- 12/12Row 5 must total 20; the kept 1 = 1 so far, so the undecided numbers (6, 4, 9) must add up to 19. The only way to make 19 is 6 + 4 + 9. So keep R5C1, R5C3, R5C6. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Oct 22, 2026
7×7 grid- 0/18Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 18 logical steps, no guessing.
- 1/18Row 4 must total 27 using 3, 8, 1, 3, 2, 7, 8. The ways to make 27 are: 3+8+1+7+8, 8+1+3+7+8. Every one uses R4C2, R4C3, R4C6, R4C7, so keep them; none uses R4C5, so remove it.
- 2/18Column 3 must total 1; the kept 1 = 1 so far, so the undecided numbers (3, 1, 8, 3, 8, 8) must add up to 0. Nothing more is needed. Remove R1C3, R2C3, R3C3, R5C3, R6C3, R7C3.
- 3/18Cream area must total 1; the kept 1 = 1 so far, so the undecided numbers (1, 8) must add up to 0. Nothing more is needed. Remove R6C2, R7C2.
- 4/18Row 1 must total 8 using 3, 5, 6, 6, 1, 3. The ways to make 8 are: 3+5, 5+3. Every one uses R1C2, so keep it; none uses R1C4, R1C5, R1C6, so remove them.
- 5/18Column 2 must total 14; the kept 5+8 = 13 so far, so the undecided numbers (5, 1, 3) must add up to 1. The only way to make 1 is 1. So keep R3C2; remove R2C2, R5C2.
- 6/18Teal area must total 12; the kept 1+8 = 9 so far, so the undecided numbers (5, 3) must add up to 3. The only way to make 3 is 3. So keep R4C1; remove R3C1.
- 7/18Row 4 must total 27; the kept 3+8+1+7+8 = 27 so far, so the undecided numbers (3) must add up to 0. Nothing more is needed. Remove R4C4.
- 8/18Row 5 must total 8 using 4, 3, 1, 3, 9. The ways to make 8 are: 4+3+1, 4+1+3. Every one uses R5C1, R5C5, so keep them; none uses R5C7, so remove it.
- 9/18Green area must total 7; the kept 4 = 4 so far, so the undecided numbers (3, 7) must add up to 3. The only way to make 3 is 3. So keep R6C1; remove R7C1.
- 10/18Row 6 must total 3; the kept 3 = 3 so far, so the undecided numbers (8, 3, 4, 6) must add up to 0. Nothing more is needed. Remove R6C4, R6C5, R6C6, R6C7.
- 11/18Brown area must total 30; the kept 7+8 = 15 so far, so the undecided numbers (9, 3, 6, 8) must add up to 15. The only way to make 15 is 9 + 6. So keep R2C6, R3C7; remove R3C6, R7C7.
- 12/18Row 2 must total 9; the kept 9 = 9 so far, so the undecided numbers (9, 7, 9, 1) must add up to 0. Nothing more is needed. Remove R2C1, R2C4, R2C5, R2C7.
- 13/18Row 7 must total 11 using 3, 8, 6. The only way to make 11 is 3 + 8. So keep R7C4, R7C5; remove R7C6.
- 14/18Row 3 must total 16; the kept 1+6 = 7 so far, so the undecided numbers (3, 9) must add up to 9. The only way to make 9 is 9. So keep R3C5; remove R3C4.
- 15/18Column 1 must total 10; the kept 3+4+3 = 10 so far, so the undecided numbers (3) must add up to 0. Nothing more is needed. Remove R1C1.
- 16/18Row 1 must total 8; the kept 5 = 5 so far, so the undecided numbers (3) must add up to 3. The only way to make 3 is 3. So keep R1C7.
- 17/18Column 4 must total 3; the kept 3 = 3 so far, so the undecided numbers (3) must add up to 0. Nothing more is needed. Remove R5C4.
- 18/18Row 5 must total 8; the kept 4+1 = 5 so far, so the undecided numbers (3) must add up to 3. The only way to make 3 is 3. So keep R5C6. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.