Everyday Grids Sums Answer Today: December 7, 2025

This page has the complete Everyday Grids Sums answers for December 7, 2025 (7 December 2025): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Dec 7, 2025 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for December 7, 2025
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Dec 7, 2025
6×6 grid- 0/12Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 12 logical steps, no guessing.
- 1/12Column 1 must total 17 using 5, 6, 6, 7, 6, 7. The ways to make 17 are: 5+6+6 (some using different copies of the same number). Every one uses R1C1, so keep it; none uses R4C1, R6C1, so remove them.
- 2/12Row 1 must total 15; the kept 5 = 5 so far, so the undecided numbers (3, 9, 5, 4, 3) must add up to 10. The only way to make 10 is 3 + 4 + 3. So keep R1C2, R1C5, R1C6; remove R1C3, R1C4.
- 3/12Column 2 must total 17; the kept 3 = 3 so far, so the undecided numbers (4, 7, 2, 6, 5) must add up to 14. The only way to make 14 is 7 + 2 + 5. So keep R3C2, R4C2, R6C2; remove R2C2, R5C2.
- 4/12Row 2 must total 19 using 6, 6, 7, 2, 3. The only way to make 19 is 6 + 6 + 7. So keep R2C1, R2C3, R2C4; remove R2C5, R2C6.
- 5/12Column 4 must total 12; the kept 7 = 7 so far, so the undecided numbers (9, 6, 6, 5) must add up to 5. The only way to make 5 is 5. So keep R6C4; remove R3C4, R4C4, R5C4.
- 6/12Row 5 must total 25 using 6, 6, 9, 4. The only way to make 25 is 6 + 6 + 9 + 4. So keep R5C1, R5C3, R5C5, R5C6.
- 7/12Row 4 must total 12; the kept 2 = 2 so far, so the undecided numbers (1, 5, 4) must add up to 10. The only way to make 10 is 1 + 5 + 4. So keep R4C3, R4C5, R4C6.
- 8/12Row 6 must total 10; the kept 5+5 = 10 so far, so the undecided numbers (2, 3, 4) must add up to 0. Nothing more is needed. Remove R6C3, R6C5, R6C6.
- 9/12Column 1 must total 17; the kept 5+6+6 = 17 so far, so the undecided numbers (6) must add up to 0. Nothing more is needed. Remove R3C1.
- 10/12Column 3 must total 13; the kept 6+1+6 = 13 so far, so the undecided numbers (5) must add up to 0. Nothing more is needed. Remove R3C3.
- 11/12Column 5 must total 18; the kept 4+5+9 = 18 so far, so the undecided numbers (1) must add up to 0. Nothing more is needed. Remove R3C5.
- 12/12Row 3 must total 8; the kept 7 = 7 so far, so the undecided numbers (1) must add up to 1. The only way to make 1 is 1. So keep R3C6. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Dec 7, 2025
7×7 grid- 0/22Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 22 logical steps, no guessing.
- 1/22Yellow area must total 9 using 3, 4, 7, 1, 3, 2. The ways to make 9 are: 3+4+2, 3+1+3+2, 4+3+2, 7+2. Every one uses R4C7, so keep it.
- 2/22Row 4 must total 12; the kept 2 = 2 so far, so the undecided numbers (8, 4, 6, 6, 1, 3) must add up to 10. The ways to make 10 are: 4+6, 6+1+3 (some using different copies of the same number). None uses R4C1, so remove it.
- 3/22Brown area must total 9 using 6, 1, 8, 1, 8. The ways to make 9 are: 1+8, 8+1 (some using different copies of the same number). None uses R1C1, so remove it.
- 4/22Column 1 must total 9 using 5, 8, 3, 2, 1. The ways to make 9 are: 5+3+1, 8+1. Every one uses R7C1, so keep it; none uses R6C1, so remove it.
- 5/22Row 1 must total 14 using 1, 8, 1, 3, 7, 3. The ways to make 14 are: 1+3+7+3, 8+3+3 (some using different copies of the same number). Every one uses R1C5, R1C7, so keep them.
- 6/22Yellow area must total 9; the kept 3+2 = 5 so far, so the undecided numbers (4, 7, 1, 3) must add up to 4. The ways to make 4 are: 4, 1+3. None uses R3C7, so remove it.
- 7/22Column 7 must total 20; the kept 3+2 = 5 so far, so the undecided numbers (4, 3, 8, 1) must add up to 15. The only way to make 15 is 4 + 3 + 8. So keep R2C7, R5C7, R6C7; remove R7C7.
- 8/22Yellow area must total 9; the kept 3+4+2 = 9 so far, so the undecided numbers (1, 3) must add up to 0. Nothing more is needed. Remove R4C5, R4C6.
- 9/22Row 7 must total 23; the kept 1 = 1 so far, so the undecided numbers (8, 9, 8, 5, 4) must add up to 22. The ways to make 22 are: 8+9+5, 9+8+5. Every one uses R7C3, R7C5, so keep them; none uses R7C6, so remove it.
- 10/22Column 5 must total 12; the kept 3+5 = 8 so far, so the undecided numbers (2, 3, 8, 1) must add up to 4. The only way to make 4 is 3 + 1. So keep R3C5, R6C5; remove R2C5, R5C5.
- 11/22Purple area must total 12; the kept 3+1+8 = 12 so far, so the undecided numbers (1, 2) must add up to 0. Nothing more is needed. Remove R5C6, R6C6.
- 12/22Row 6 must total 19; the kept 1+8 = 9 so far, so the undecided numbers (6, 4, 8) must add up to 10. The only way to make 10 is 6 + 4. So keep R6C2, R6C3; remove R6C4.
- 13/22Teal area must total 13; the kept 5 = 5 so far, so the undecided numbers (8) must add up to 8. The only way to make 8 is 8. So keep R7C4.
- 14/22Row 7 must total 23; the kept 1+9+8+5 = 23 so far, so the undecided numbers (8) must add up to 0. Nothing more is needed. Remove R7C2.
- 15/22Column 2 must total 23; the kept 6 = 6 so far, so the undecided numbers (1, 8, 1, 4, 4) must add up to 17. The ways to make 17 are: 1+8+4+4, 8+1+4+4. Every one uses R2C2, R4C2, R5C2, so keep them.
- 16/22Row 5 must total 7; the kept 4+3 = 7 so far, so the undecided numbers (3, 7, 4) must add up to 0. Nothing more is needed. Remove R5C1, R5C3, R5C4.
- 17/22Column 4 must total 15; the kept 8 = 8 so far, so the undecided numbers (1, 5, 3, 6) must add up to 7. The only way to make 7 is 1 + 6. So keep R1C4, R4C4; remove R2C4, R3C4.
- 18/22Row 1 must total 14; the kept 1+3+3 = 7 so far, so the undecided numbers (1, 8, 7) must add up to 7. The only way to make 7 is 7. So keep R1C6; remove R1C2, R1C3.
- 19/22Row 2 must total 22; the kept 8+4 = 12 so far, so the undecided numbers (5, 9, 1) must add up to 10. The only way to make 10 is 9 + 1. So keep R2C3, R2C6; remove R2C1.
- 20/22Column 3 must total 30; the kept 9+4+9 = 22 so far, so the undecided numbers (8, 6) must add up to 8. The only way to make 8 is 8. So keep R3C3; remove R4C3.
- 21/22Green area must total 14; the kept 4+1 = 5 so far, so the undecided numbers (8, 1) must add up to 9. The only way to make 9 is 8 + 1. So keep R3C1, R3C2.
- 22/22Row 3 must total 20; the kept 8+1+8+3 = 20 so far, so the undecided numbers (8) must add up to 0. Nothing more is needed. Remove R3C6. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.