Everyday Grids Sums Answer Today: August 3, 2025

This page has the complete Everyday Grids Sums answers for August 3, 2025 (3 August 2025): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Aug 3, 2025 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for August 3, 2025
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Aug 3, 2025
6×6 grid- 0/10Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 10 logical steps, no guessing.
- 1/10Row 1 must total 24 using 5, 5, 4, 3, 9, 6. The ways to make 24 are: 5+4+9+6 (some using different copies of the same number). Every one uses R1C3, R1C5, R1C6, so keep them; none uses R1C4, so remove it.
- 2/10Column 4 must total 8 using 3, 9, 3, 2, 7. The only way to make 8 is 3 + 3 + 2. So keep R2C4, R4C4, R5C4; remove R3C4, R6C4.
- 3/10Row 2 must total 17; the kept 3 = 3 so far, so the undecided numbers (7, 4, 6, 9, 8) must add up to 14. The only way to make 14 is 6 + 8. So keep R2C3, R2C6; remove R2C1, R2C2, R2C5.
- 4/10Column 5 must total 17; the kept 9 = 9 so far, so the undecided numbers (9, 3, 9, 5) must add up to 8. The only way to make 8 is 3 + 5. So keep R4C5, R6C5; remove R3C5, R5C5.
- 5/10Row 4 must total 11; the kept 3+3 = 6 so far, so the undecided numbers (5, 7, 9, 8) must add up to 5. The only way to make 5 is 5. So keep R4C1; remove R4C2, R4C3, R4C6.
- 6/10Row 5 must total 15; the kept 2 = 2 so far, so the undecided numbers (2, 7, 3, 4) must add up to 13. The only way to make 13 is 2 + 7 + 4. So keep R5C1, R5C2, R5C6; remove R5C3.
- 7/10Row 6 must total 23; the kept 5 = 5 so far, so the undecided numbers (6, 9, 8, 4) must add up to 18. The only way to make 18 is 6 + 8 + 4. So keep R6C1, R6C3, R6C6; remove R6C2.
- 8/10Column 1 must total 17; the kept 5+2+6 = 13 so far, so the undecided numbers (5, 4) must add up to 4. The only way to make 4 is 4. So keep R3C1; remove R1C1.
- 9/10Row 3 must total 5; the kept 4 = 4 so far, so the undecided numbers (1, 5, 2) must add up to 1. The only way to make 1 is 1. So keep R3C2; remove R3C3, R3C6.
- 10/10Row 1 must total 24; the kept 4+9+6 = 19 so far, so the undecided numbers (5) must add up to 5. The only way to make 5 is 5. So keep R1C2. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Aug 3, 2025
7×7 grid- 0/17Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 17 logical steps, no guessing.
- 1/17Peach area must total 29 using 3, 8, 2, 5, 9, 2, 5. The ways to make 29 are: 3+8+2+5+9+2, 3+8+2+9+2+5, 8+2+5+9+5, 8+5+9+2+5. Every one uses R1C3, R2C4, so keep them.
- 2/17Green area must total 25 using 7, 2, 7, 8, 9, 9. The ways to make 25 are: 7+2+7+9, 7+9+9 (some using different copies of the same number). None uses R4C1, so remove it.
- 3/17Column 1 must total 33 using 7, 2, 7, 9, 9, 8. The ways to make 33 are: 7+2+7+9+8, 7+9+9+8 (some using different copies of the same number). Every one uses R7C1, so keep it.
- 4/17Brown area must total 12; the kept 8 = 8 so far, so the undecided numbers (4, 2, 4, 4) must add up to 4. The ways to make 4 are: 4 (some using different copies of the same number). None uses R6C2, so remove it.
- 5/17Column 3 must total 13; the kept 8 = 8 so far, so the undecided numbers (5, 1, 1, 4, 4, 9) must add up to 5. There are 5 ways to make 5. None uses R7C3, so remove it.
- 6/17Cream area must total 16 using 1, 4, 7, 7, 2. The only way to make 16 is 7 + 7 + 2. So keep R6C5, R7C4, R7C5; remove R5C4, R6C4.
- 7/17Column 4 must total 23; the kept 9+7 = 16 so far, so the undecided numbers (2, 2, 5) must add up to 7. The ways to make 7 are: 2+5 (some using different copies of the same number). Every one uses R4C4, so keep it.
- 8/17Row 4 must total 18; the kept 5 = 5 so far, so the undecided numbers (6, 1, 7, 2, 9) must add up to 13. The only way to make 13 is 6 + 7. So keep R4C2, R4C5; remove R4C3, R4C6, R4C7.
- 9/17Teal area must total 9; the kept 7 = 7 so far, so the undecided numbers (6, 2, 6, 3, 1) must add up to 2. The only way to make 2 is 2. So keep R5C6; remove R5C5, R6C6, R7C6, R7C7.
- 10/17Row 6 must total 17; the kept 7 = 7 so far, so the undecided numbers (9, 4, 1) must add up to 10. The only way to make 10 is 9 + 1. So keep R6C1, R6C7; remove R6C3.
- 11/17Column 6 must total 7; the kept 2 = 2 so far, so the undecided numbers (3, 4, 5) must add up to 5. The only way to make 5 is 5. So keep R3C6; remove R1C6, R2C6.
- 12/17Row 1 must total 21; the kept 8 = 8 so far, so the undecided numbers (7, 3, 2, 9, 2) must add up to 13. The only way to make 13 is 2 + 9 + 2. So keep R1C4, R1C5, R1C7; remove R1C1, R1C2.
- 13/17Column 1 must total 33; the kept 9+8 = 17 so far, so the undecided numbers (2, 7, 9) must add up to 16. The only way to make 16 is 7 + 9. So keep R3C1, R5C1; remove R2C1.
- 14/17Row 3 must total 16; the kept 7+5 = 12 so far, so the undecided numbers (8, 1, 2, 7, 4) must add up to 4. The only way to make 4 is 4. So keep R3C7; remove R3C2, R3C3, R3C4, R3C5.
- 15/17Row 2 must total 19; the kept 9 = 9 so far, so the undecided numbers (5, 5, 2, 6) must add up to 10. The only way to make 10 is 5 + 5. So keep R2C2, R2C3; remove R2C5, R2C7.
- 16/17Column 2 must total 19; the kept 5+6 = 11 so far, so the undecided numbers (4, 4) must add up to 8. The only way to make 8 is 4 + 4. So keep R5C2, R7C2.
- 17/17Row 5 must total 21; the kept 9+4+2 = 15 so far, so the undecided numbers (4, 6) must add up to 6. The only way to make 6 is 6. So keep R5C7; remove R5C3. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.