# Math riddles Level 61 Answer with Hints and solutions

Math riddles game level 61 Answer with solution android game developed by Black games. Scroll Below to find details.

Math Riddles tests your IQ with mathematical puzzles. Challenge yourself with different levels of math puzzles and stretch the limits of your intelligence. Every IQ game is prepared with an approach of an IQ test. Improve your mathematics, challenge your brain with this game. There are many hard levels which you may not have solved then you can take help from here.

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**Math app level 61**:

**Update:** they Now changed the level little bit:

A-4B+2C=16

2A+7B-5C=83

A+B-C=?

**Answer**: 33

**Solution (new):**

Update: I have now removed an old answer, And giving you the detailed solution to this level:

**This Solution is provided by one of the users names Taraarata in comments:**

a-4b+2c = 16

2a+7b-5c = 83

———————— +

3a +3b-3c = 99

So…..

a + b – c = 33

So the answer is 33

**My Solution:**

- There are 3 variable so we need minimum 3 equations to get the value of each variable (A B and C)
- Now we have only two equations, We can only find a relation between the variables.
- So after using
**A=2n**(for integral value), I Found the following relationship:

**A=2n, B=3n-41, C=5n-74**

Now for each value of** n,** they will satisfy both given equations, For example taking **n=1**

**A**=2×1=**2**

**B**=3×1-41= **-38**

**C**=5n-74= **-69**

So A+B-C

= 2+(-38)-(-69)

=2-38+69

=33

Now understood?????? Or still, have a doubt?

**Okay, **let us take another value of n, Let’s take n=0 (simplest)

A=0, B=-41, C=-74

A+B-C= 0-41+74=33 (again!)

try this with N=100 you will be surprised that answer is always 33

So those who are asking the exact value of A B and C, I want to tell you that there can not be any fixed value, you can take any value of A and solve for the other two, but the answer will always be 33.

If there is any Doubt/discrepancy then please let me know in comments or you are unable to understand the solution then I will surely help you.

I used a different method but the good ole addition method works too.

I first solved for A:

A – 4B + 2C = 16

A = 16 + 4B – 2C

Next replaced the A in 2A with what A is equivalent too:

2(16 + 4B – 2C) + 7B – 5C = 83

Then I started solving for 5B (Prevent Fractions):

32 + 8B – 4C + 7B – 5C = 83

15B – 9C = 51

3(5B – 3C = 17)

5B = 17 + 3C

Then I Resolved the first equation for 4B (Prevent Fractions):

A – 4B + 2C = 16

4B = A + 2C – 16

Then I noticed 5B is one B more than 4B So I set 5B equal to 4B + B

17 + 3C = A + 2C – 16 + B

33 + 3C = A + 2C + B

33 + C = A + B

Then I noticed that I was solving for A + B – C

So I replaced A + B with 33 + C

And came with 33 + C – C = ?

C’s cancel out and 33 = ?

I know this is a long, and not the best way to do it. But I like finding alternatives!

Can someone explain how the relationship of “A=2n, B=3n-41, C=5n-74” was reached?

Put value of A=n, then solve remaining 2 equations. You will get values of B and C in terms of n, But to get interger values, I have taken A=2n

Dude why its so hard…

I dont need “n” or something

Because it so hard for me..hohoo

I think it just

a-4b+2c = 16

2a+7b-5c = 83

————————+

3a +3b-3c = 99

So…..

a + b – c = 33

So answer is 33

This has to be the intended answer for this, regardless if I think it is right, as there is no way they jump from simple squares to the relationships in the answer above.

It works :

A = 30

B = 4

C = 3

Yes for N=15, It gives these values

Its 33 i dont know how i tried many solutions

No clue what you’re saying in the answer for the new answer could you put it differently?

And give the actual value of each letter pls

a = 2 n, b = 3 n – 41, c = 5 n – 74,

this is the value of each letter

N can be anything here you can take zero

so a=0, b=-41, c= -74

a-4b+2c=16

2a+7b-5c=83

3a+3b-3c=99

A+b-c=99/3 =33

You don’t need to know x=, y= or z =…

1x -4y -1z = 5

2x +7y -2z = 16

________________+

3x +3y -3z = 21

/3

X + y -z = 7 zo you have the answer!

yes, You are correct, thats what my equations say indirectly. But some users need to know everything that how to solve the question for each shape.

I just solved in another way..but no idea where A= 2n equation come from

Yes there must be another way, Can you share with all so that I can add it to post?

No, not at all. I cannot solve for this equation given the information. x comes out as 5 + 4y and y comes out as 6/15… And how would x – 4y = 5 jive with x + y = 7?

I do not accept this answer, nor should anyone else given the thorough explanation on every other solution.

are you serious, did you solve it correctly??

y=2/5 and x=33/5 , these are the solution for x and y and hence x+y=7, i have another easy method for doing this, that i have added to post itself.

I tried solving it using the good ol’ trial and error and got a different answer.

I came up with:

A = 50

B = 4

C = 9

A-4B+2C=16

50 – 4(4) + 2(9) = 16

50 – 16 + 18 = 16

2A+7B-5C=83

2(50) + 7(4) – 5(9) =83

100 + 28 – 45 = 83

A+B-C=?

50 + 4 – 9 = 45

It all checks out. But I suppose that is the wrong way of solving it?

50-16+18=52

Not 16

How come? MDAS does not apply?

If the expression was 50-(16+18) then it would have been correct

MDAS states that you do MD in order from left to right and AS from left to right.

That is why MD and AS are grouped together.

Consider this:

1+2-2 is the same as 1 + 2 + (-2)

2 * 2 / 2 is the same as 2 * 2 * (1/2)

Basically MD and AS are inverses of each other, so you do them in order from Left to Right