Everyday Grids Zip Answer Today: November 13, 2024

This page has the complete Everyday Grids Zip answers for November 13, 2024 (13 November 2024): the solved grids for both the Normal and Hard Zip levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Zip guide? It’s all below, and each Everyday Grids Zip solution is verified against the puzzle rules, so it matches the Nov 13, 2024 puzzle in the app exactly.
About Everyday Grids Zip
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Zip is one of them. Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can’t cross walls. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Zip puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Zip Answers and Solutions for November 13, 2024
Each level below shows the solved Zip grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Zip Normal Answer, Nov 13, 2024
7×7 grid- 0/63Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 63 logical steps, no guessing.
- 1/63Seed 11 (R1C1) needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/63R1C7 needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 3/63R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 4/63R4C1 needs two connections (in and out). Closed sides, left: edge of the board; down: wall. So the path must go up and right from here.
- 5/63Dot 10 at R3C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 6/63R4C3 needs two connections (in and out). Closed sides, left: wall, down: wall. So the path must go up and right from here.
- 7/63R5C1 needs two connections (in and out). Closed sides, left: edge of the board; up: wall. So the path must go right and down from here.
- 8/63R6C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 9/63Seed 3 (R6C2) needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 10/63R7C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 11/63R7C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 12/63Linking R4C2 and R5C2 is impossible: it would put the numbers in the order 11→10→4→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 13/63R4C2 needs two connections (in and out). Closed sides, right: wall, down: it would put the numbers in the order 11→10→4→3 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 14/63Seed 4 (R5C2) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 11→10→4→3 on one stretch of path, but they must be visited in sequence, down: wall. So the path must go left and right from here.
- 15/63Linking R5C3 and R6C3 is impossible: it would close a loop. Mark that side closed.
- 16/63R5C3 needs two connections (in and out). Closed sides, up: wall, down: it would close a loop. So the path must go left and right from here.
- 17/63Linking R6C3 and R7C3 is impossible: it would put the numbers in the order 4→3→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 18/63R6C3 needs two connections (in and out). Closed sides, up: it would close a loop, down: it would put the numbers in the order 4→3→1 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 19/63As the start, seed 1 (R7C3) needs exactly one connection. Closed sides, down: edge of the board; up: it would put the numbers in the order 4→3→1 on one stretch of path, but they must be visited in sequence, left: R7C2 already has its two connections. So the path must go right from here.
- 20/63Linking R6C6 and R6C7 is impossible: it would connect seed 5 straight to seed 14. Mark that side closed.
- 21/63Seed 14 (R6C7) needs two connections (in and out). Closed sides, right: edge of the board; left: it would connect seed 5 straight to seed 14. So the path must go up and down from here.
- 22/63Dot 15 at R7C7 already has its one connection, it is the finish of the path, so the path cannot use its other side(s). Mark them as closed.
- 23/63R7C6 needs two connections (in and out). Closed sides, down: edge of the board; right: R7C7 already has its single connection (it is an end of the path). So the path must go up and left from here.
- 24/63Linking R5C6 and R5C7 is impossible: it would put the numbers in the order 6→14→15 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 25/63R5C7 needs two connections (in and out). Closed sides, right: edge of the board; left: it would put the numbers in the order 6→14→15 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 26/63Linking R7C4 and R7C5 is impossible: it would put the numbers in the order 1→5 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 27/63R7C4 needs two connections (in and out). Closed sides, down: edge of the board; right: it would put the numbers in the order 1→5 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 28/63Dot 2 at R6C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 29/63R7C5 needs two connections (in and out). Closed sides, down: edge of the board; left: it would put the numbers in the order 1→5 on one stretch of path, but they must be visited in sequence. So the path must go up and right from here.
- 30/63Linking R6C5 and R6C6 is impossible: it would close a loop. Mark that side closed.
- 31/63R6C5 needs two connections (in and out). Closed sides, left: R6C4 already has its two connections, right: it would close a loop. So the path must go up and down from here.
- 32/63Seed 5 (R6C6) needs two connections (in and out). Closed sides, left: it would close a loop, right: it would connect seed 5 straight to seed 14. So the path must go up and down from here.
- 33/63Linking R5C5 and R5C6 is impossible: it would close a loop. Mark that side closed.
- 34/63Seed 6 (R5C6) needs two connections (in and out). Closed sides, left: it would close a loop, right: it would put the numbers in the order 6→14→15 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 35/63Linking R4C6 and R4C7 is impossible: it would put the numbers in the order 5→6→14→15 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 36/63R4C7 needs two connections (in and out). Closed sides, right: edge of the board; left: it would put the numbers in the order 5→6→14→15 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 37/63Check: if the path did NOT use the link R2C2–R2C3, then after 1 forced move the path would close into a loop. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 38/63Check: if the path did NOT use the link R2C5–R2C6, then after 1 forced move the path would close into a loop. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 39/63Check: if the path did NOT use the link R3C5–R3C6, then after 1 forced move the numbers 5→6→13→14→15 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 40/63Linking R3C6 and R3C7 is impossible: it would put the numbers in the order 7→13→14→15 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 41/63R3C6 needs two connections (in and out). Closed sides, up: wall, right: it would put the numbers in the order 7→13→14→15 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 42/63R4C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 43/63Seed 13 (R3C7) needs two connections (in and out). Closed sides, right: edge of the board; left: it would put the numbers in the order 7→13→14→15 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 44/63R2C7 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 45/63R2C6 needs two connections (in and out). Closed sides, right: R2C7 already has its two connections, down: wall. So the path must go up and left from here.
- 46/63R1C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 47/63R1C5 needs two connections (in and out). Closed sides, up: edge of the board; right: R1C6 already has its two connections. So the path must go left and down from here.
- 48/63R2C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 49/63Check: if the path used the link R1C3–R2C3, then after 2 forced moves the numbers 8→12→13→14→15 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 50/63R1C3 needs two connections (in and out). Closed sides, up: edge of the board; down: leads to a contradiction. So the path must go left and right from here.
- 51/63R1C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 52/63Dot 12 at R1C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 53/63R2C2 needs two connections (in and out). Closed sides, up: R1C2 already has its two connections, left: wall. So the path must go right and down from here.
- 54/63Dot 9 at R3C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 55/63R2C3 needs two connections (in and out). Closed sides, up: leads to a contradiction, down: wall. So the path must go left and right from here.
- 56/63R2C4 needs two connections (in and out). Closed sides, up: R1C4 already has its two connections, right: R2C5 already has its two connections. So the path must go left and down from here.
- 57/63R3C3 needs two connections (in and out). Closed sides, up: wall, left: R3C2 already has its two connections. So the path must go right and down from here.
- 58/63Dot 8 at R3C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 59/63Seed 7 (R3C5) needs two connections (in and out). Closed sides, up: R2C5 already has its two connections, left: R3C4 already has its two connections. So the path must go right and down from here.
- 60/63Linking R4C4 and R5C4 is impossible: it would put the numbers in the order 15→14→13→12→11→10→9→8→4→3→2→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 61/63R4C4 needs two connections (in and out). Closed sides, up: wall, down: it would put the numbers in the order 15→14→13→12→11→10→9→8→4→3→2→1 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 62/63R4C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 63/63R5C4 needs two connections (in and out). Closed sides, up: it would put the numbers in the order 15→14→13→12→11→10→9→8→4→3→2→1 on one stretch of path, but they must be visited in sequence, down: wall. So the path must go left and right from here. ✅ Solved!
Zip Normal answer as text
Everyday Grids Zip Hard Answer, Nov 13, 2024
5×5 grid- 0/25Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 25 logical steps, no guessing.
- 1/25R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/25Seed 2 (R1C5) needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 3/25R2C3 needs two connections (in and out). Closed sides, right: wall, down: wall. So the path must go up and left from here.
- 4/25R2C5 needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 5/25R3C5 needs two connections (in and out). Closed sides, right: edge of the board; up: wall. So the path must go left and down from here.
- 6/25R4C5 needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 7/25Dot 1 at R4C4 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 8/25R5C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 9/25R5C2 needs two connections (in and out). Closed sides, down: edge of the board; up: wall. So the path must go left and right from here.
- 10/25R5C4 needs two connections (in and out). Closed sides, down: edge of the board; up: R4C4 already has its single connection (it is an end of the path). So the path must go left and right from here.
- 11/25R5C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 12/25R4C3 needs two connections (in and out). Closed sides, right: R4C4 already has its single connection (it is an end of the path), down: R5C3 already has its two connections. So the path must go up and left from here.
- 13/25Linking R1C4 and R2C4 is impossible: it would close a loop. Mark that side closed.
- 14/25R1C4 needs two connections (in and out). Closed sides, up: edge of the board; down: it would close a loop. So the path must go left and right from here.
- 15/25R1C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 16/25R1C2 needs two connections (in and out). Closed sides, up: edge of the board; right: R1C3 already has its two connections. So the path must go left and down from here.
- 17/25R2C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 18/25R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: R2C2 already has its two connections. So the path must go up and down from here.
- 19/25R2C4 needs two connections (in and out). Closed sides, up: it would close a loop, left: wall. So the path must go right and down from here.
- 20/25R3C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 21/25R3C3 needs two connections (in and out). Closed sides, up: wall, right: R3C4 already has its two connections. So the path must go left and down from here.
- 22/25Linking R3C1 and R4C1 is impossible: it would join the start (1) to the finish (4) before every cell is visited. Mark that side closed.
- 23/25Seed 3 (R3C1) needs two connections (in and out). Closed sides, left: edge of the board; down: it would join the start (1) to the finish (4) before every cell is visited. So the path must go up and right from here.
- 24/25R3C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 25/25R4C1 needs two connections (in and out). Closed sides, left: edge of the board; up: it would join the start (1) to the finish (4) before every cell is visited. So the path must go right and down from here. ✅ Solved!
Zip Hard answer as text
How to Solve Everyday Grids Zip: Quick Tips
- Start with cells that have only two open sides, the path is forced straight through them.
- Corners and dead-end pockets between walls must be entered and left immediately, so draw those links first.
- Never join two path pieces into a loop, and never connect numbers out of order.
- If a group of cells has only one way in, the path must use it, or that group would be left unvisited.