Everyday Grids Zip Answer Today: March 15, 2025

This page has the complete Everyday Grids Zip answers for March 15, 2025 (15 March 2025): the solved grids for both the Normal and Hard Zip levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Zip guide? It’s all below, and each Everyday Grids Zip solution is verified against the puzzle rules, so it matches the Mar 15, 2025 puzzle in the app exactly.
About Everyday Grids Zip
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Zip is one of them. Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can’t cross walls. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Zip puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Zip Answers and Solutions for March 15, 2025
Each level below shows the solved Zip grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Zip Normal Answer, Mar 15, 2025
8×8 grid- 0/76Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 76 logical steps, no guessing.
- 1/76R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/76Seed 19 (R1C8) needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 3/76R3C7 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 4/76R3C8 needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 5/76R2C8 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 6/76R4C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 7/76Seed 16 (R4C7) needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 8/76Seed 18 (R4C8) needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 9/76Seed 10 (R5C1) needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 10/76R5C4 needs two connections (in and out). Closed sides, right: wall, down: wall. So the path must go up and left from here.
- 11/76R5C8 needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 12/76R6C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 13/76Seed 12 (R7C5) needs two connections (in and out). Closed sides, up: wall, right: wall. So the path must go left and down from here.
- 14/76R7C6 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 15/76R8C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 16/76R7C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 17/76R8C4 needs two connections (in and out). Closed sides, down: edge of the board; right: wall. So the path must go up and left from here.
- 18/76R7C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 19/76Seed 5 (R6C4) needs two connections (in and out). Closed sides, up: wall, down: R7C4 already has its two connections. So the path must go left and right from here.
- 20/76R7C3 needs two connections (in and out). Closed sides, up: wall, right: R7C4 already has its two connections. So the path must go left and down from here.
- 21/76R8C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 22/76Seed 11 (R8C2) needs two connections (in and out). Closed sides, down: edge of the board; right: R8C3 already has its two connections. So the path must go up and left from here.
- 23/76R7C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 24/76R6C2 needs two connections (in and out). Closed sides, left: wall, down: R7C2 already has its two connections. So the path must go up and right from here.
- 25/76R6C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 26/76R8C5 needs two connections (in and out). Closed sides, down: edge of the board; left: wall. So the path must go up and right from here.
- 27/76R8C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 28/76R8C7 needs two connections (in and out). Closed sides, down: edge of the board; left: R8C6 already has its two connections. So the path must go up and right from here.
- 29/76R8C8 needs two connections (in and out). Closed sides, down/right: edge of the board. So the path must go up and left from here.
- 30/76Linking R1C3 and R1C4 is impossible: it would connect seed 8 straight to seed 1. Mark that side closed.
- 31/76Seed 8 (R1C3) needs two connections (in and out). Closed sides, up: edge of the board; right: it would connect seed 8 straight to seed 1. So the path must go left and down from here.
- 32/76R1C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 33/76Linking R1C4 and R1C5 is impossible: it would connect seed 1 straight to seed 20. Mark that side closed.
- 34/76As the start, seed 1 (R1C4) needs exactly one connection. Closed sides, up: edge of the board; left: it would connect seed 8 straight to seed 1, right: it would connect seed 1 straight to seed 20. So the path must go down from here.
- 35/76Linking R1C5 and R2C5 is impossible: it would connect seed 20 straight to seed 15. Mark that side closed.
- 36/76As the finish, seed 20 (R1C5) needs exactly one connection. Closed sides, up: edge of the board; left: it would connect seed 1 straight to seed 20, down: it would connect seed 20 straight to seed 15. So the path must go right from here.
- 37/76Linking R1C7 and R2C7 is impossible: it would put the numbers in the order 18→19→16 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 38/76R1C7 needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 18→19→16 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 39/76R1C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 40/76R2C7 needs two connections (in and out). Closed sides, up: it would put the numbers in the order 18→19→16 on one stretch of path, but they must be visited in sequence, right: R2C8 already has its two connections. So the path must go left and down from here.
- 41/76Linking R2C3 and R2C4 is impossible: it would put the numbers in the order 9→8→2→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 42/76Linking R2C4 and R2C5 is impossible: it would put the numbers in the order 1→2→15 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 43/76Seed 2 (R2C4) needs two connections (in and out). Closed sides, left: it would put the numbers in the order 9→8→2→1 on one stretch of path, but they must be visited in sequence, right: it would put the numbers in the order 1→2→15 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 44/76Seed 15 (R2C5) needs two connections (in and out). Closed sides, up: it would connect seed 20 straight to seed 15, left: it would put the numbers in the order 1→2→15 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 45/76R2C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 46/76Seed 14 (R3C6) needs two connections (in and out). Closed sides, up: R2C6 already has its two connections, right: wall. So the path must go left and down from here.
- 47/76R3C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 48/76Linking R3C1 and R3C2 is impossible: it would put the numbers in the order 12→11→10→7 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 49/76R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: it would put the numbers in the order 12→11→10→7 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 50/76Dot 9 at R2C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 51/76R2C2 needs two connections (in and out). Closed sides, up: R1C2 already has its two connections, left: R2C1 already has its two connections. So the path must go right and down from here.
- 52/76R2C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 53/76Linking R3C4 and R4C4 is impossible: it would put the numbers in the order 1→2→4→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 54/76R3C4 needs two connections (in and out). Closed sides, right: R3C5 already has its two connections, down: it would put the numbers in the order 1→2→4→3 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 55/76Linking R3C2 and R3C3 is impossible: it would put the numbers in the order 12→11→10→9→8→7→2→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 56/76Seed 7 (R3C2) needs two connections (in and out). Closed sides, left: it would put the numbers in the order 12→11→10→7 on one stretch of path, but they must be visited in sequence, right: it would put the numbers in the order 12→11→10→9→8→7→2→1 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 57/76R3C3 needs two connections (in and out). Closed sides, up: R2C3 already has its two connections, left: it would put the numbers in the order 12→11→10→9→8→7→2→1 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 58/76Linking R4C2 and R4C3 is impossible: it would put the numbers in the order 12→11→10→9→8→7→2→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 59/76R4C2 needs two connections (in and out). Closed sides, left: wall, right: it would put the numbers in the order 12→11→10→9→8→7→2→1 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 60/76Dot 6 at R5C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 61/76Seed 3 (R5C3) needs two connections (in and out). Closed sides, left: R5C2 already has its two connections, down: R6C3 already has its two connections. So the path must go up and right from here.
- 62/76R4C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 63/76Seed 4 (R4C4) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 1→2→4→3 on one stretch of path, but they must be visited in sequence, left: R4C3 already has its two connections. So the path must go right and down from here.
- 64/76Linking R4C5 and R4C6 is impossible: it would put the numbers in the order 1→2→3→4→14→15→16 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 65/76R4C5 needs two connections (in and out). Closed sides, up: wall, right: it would put the numbers in the order 1→2→3→4→14→15→16 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 66/76R4C6 needs two connections (in and out). Closed sides, left: it would put the numbers in the order 1→2→3→4→14→15→16 on one stretch of path, but they must be visited in sequence, right: wall. So the path must go up and down from here.
- 67/76Linking R5C5 and R5C6 is impossible: it would put the numbers in the order 1→2→3→4→13→14→15→16 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 68/76R5C5 needs two connections (in and out). Closed sides, left: wall, right: it would put the numbers in the order 1→2→3→4→13→14→15→16 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 69/76R6C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 70/76R6C6 needs two connections (in and out). Closed sides, left: R6C5 already has its two connections, right: wall. So the path must go up and down from here.
- 71/76Dot 13 at R5C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 72/76R5C7 needs two connections (in and out). Closed sides, left: R5C6 already has its two connections, right: wall. So the path must go up and down from here.
- 73/76Linking R6C7 and R6C8 is impossible: it would join the start (1) to the finish (20) before every cell is visited. Mark that side closed.
- 74/76Seed 17 (R6C7) needs two connections (in and out). Closed sides, left: wall, right: it would join the start (1) to the finish (20) before every cell is visited. So the path must go up and down from here.
- 75/76R7C7 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 76/76R6C8 needs two connections (in and out). Closed sides, right: edge of the board; left: it would join the start (1) to the finish (20) before every cell is visited. So the path must go up and down from here. ✅ Solved!
Zip Normal answer as text
Everyday Grids Zip Hard Answer, Mar 15, 2025
6×6 grid- 0/36Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 36 logical steps, no guessing.
- 1/36R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/36R1C2 needs two connections (in and out). Closed sides, up: edge of the board; right: wall. So the path must go left and down from here.
- 3/36R1C3 needs two connections (in and out). Closed sides, up: edge of the board; left: wall. So the path must go right and down from here.
- 4/36R1C5 needs two connections (in and out). Closed sides, up: edge of the board; down: wall. So the path must go left and right from here.
- 5/36R1C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 6/36R1C6 needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 7/36R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 8/36R2C2 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 9/36R2C4 needs two connections (in and out). Closed sides, up: R1C4 already has its two connections, right: wall. So the path must go left and down from here.
- 10/36R2C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 11/36R2C5 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 12/36R3C4 needs two connections (in and out). Closed sides, right: wall, down: wall. So the path must go up and left from here.
- 13/36R5C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 14/36R5C2 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 15/36Seed 5 (R5C3) needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 16/36R5C6 needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 17/36R6C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 18/36R6C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 19/36R6C3 needs two connections (in and out). Closed sides, down: edge of the board; left: R6C2 already has its two connections. So the path must go up and right from here.
- 20/36As the finish, seed 6 (R6C6) needs exactly one connection. Closed sides, down/right: edge of the board; up: wall. So the path must go left from here.
- 21/36Linking R3C1 and R3C2 is impossible: it would close a loop. Mark that side closed.
- 22/36R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: it would close a loop. So the path must go up and down from here.
- 23/36Dot 3 at R4C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 24/36R3C2 needs two connections (in and out). Closed sides, left: it would close a loop, down: wall. So the path must go up and right from here.
- 25/36R3C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 26/36Seed 4 (R4C2) needs two connections (in and out). Closed sides, up: wall, left: R4C1 already has its two connections. So the path must go right and down from here.
- 27/36R4C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 28/36R4C4 needs two connections (in and out). Closed sides, up: wall, left: R4C3 already has its two connections. So the path must go right and down from here.
- 29/36Linking R3C5 and R3C6 is impossible: it would put the numbers in the order 5→4→3→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 30/36R3C5 needs two connections (in and out). Closed sides, left: wall, right: it would put the numbers in the order 5→4→3→1 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 31/36Dot 2 at R4C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 32/36As the start, seed 1 (R3C6) needs exactly one connection. Closed sides, right: edge of the board; up: wall, left: it would put the numbers in the order 5→4→3→1 on one stretch of path, but they must be visited in sequence. So the path must go down from here.
- 33/36Linking R5C4 and R6C4 is impossible: it would close a loop. Mark that side closed.
- 34/36R5C4 needs two connections (in and out). Closed sides, left: wall, down: it would close a loop. So the path must go up and right from here.
- 35/36R5C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 36/36R6C4 needs two connections (in and out). Closed sides, down: edge of the board; up: it would close a loop. So the path must go left and right from here. ✅ Solved!
Zip Hard answer as text
How to Solve Everyday Grids Zip: Quick Tips
- Start with cells that have only two open sides, the path is forced straight through them.
- Corners and dead-end pockets between walls must be entered and left immediately, so draw those links first.
- Never join two path pieces into a loop, and never connect numbers out of order.
- If a group of cells has only one way in, the path must use it, or that group would be left unvisited.