Everyday Grids Zip Answer Today: January 21, 2026

This page has the complete Everyday Grids Zip answers for January 21, 2026 (21 January 2026): the solved grids for both the Normal and Hard Zip levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Zip guide? It’s all below, and each Everyday Grids Zip solution is verified against the puzzle rules, so it matches the Jan 21, 2026 puzzle in the app exactly.
About Everyday Grids Zip
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Zip is one of them. Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can’t cross walls. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Zip puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Zip Answers and Solutions for January 21, 2026
Each level below shows the solved Zip grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Zip Normal Answer, Jan 21, 2026
7×7 grid- 0/56Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 56 logical steps, no guessing.
- 1/56R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/56R1C2 needs two connections (in and out). Closed sides, up: edge of the board; right: wall. So the path must go left and down from here.
- 3/56R1C3 needs two connections (in and out). Closed sides, up: edge of the board; left: wall. So the path must go right and down from here.
- 4/56Seed 3 (R1C5) needs two connections (in and out). Closed sides, up: edge of the board; down: wall. So the path must go left and right from here.
- 5/56R1C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 6/56R1C7 needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 7/56R1C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 8/56R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 9/56R2C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 10/56R2C2 needs two connections (in and out). Closed sides, left: R2C1 already has its two connections, down: wall. So the path must go up and right from here.
- 11/56R2C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 12/56R2C4 needs two connections (in and out). Closed sides, up: R1C4 already has its two connections, left: R2C3 already has its two connections. So the path must go right and down from here.
- 13/56R3C2 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 14/56R7C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 15/56R7C5 needs two connections (in and out). Closed sides, down: edge of the board; right: wall. So the path must go up and left from here.
- 16/56R7C6 needs two connections (in and out). Closed sides, down: edge of the board; left: wall. So the path must go up and right from here.
- 17/56Seed 7 (R7C7) needs two connections (in and out). Closed sides, down/right: edge of the board. So the path must go up and left from here.
- 18/56Linking R2C5 and R2C6 is impossible: it would put the numbers in the order 12→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 19/56Seed 12 (R2C5) needs two connections (in and out). Closed sides, up: wall, right: it would put the numbers in the order 12→1 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 20/56Linking R2C6 and R2C7 is impossible: it would put the numbers in the order 1→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 21/56As the start, seed 1 (R2C6) needs exactly one connection. Closed sides, up: R1C6 already has its two connections, left: it would put the numbers in the order 12→1 on one stretch of path, but they must be visited in sequence, right: it would put the numbers in the order 1→3 on one stretch of path, but they must be visited in sequence. So the path must go down from here.
- 22/56R2C7 needs two connections (in and out). Closed sides, right: edge of the board; left: it would put the numbers in the order 1→3 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 23/56Linking R3C4 and R4C4 is impossible: it would put the numbers in the order 11→12→10 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 24/56R3C4 needs two connections (in and out). Closed sides, right: wall, down: it would put the numbers in the order 11→12→10 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 25/56R3C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 26/56Linking R3C5 and R3C6 is impossible: it would put the numbers in the order 12→11→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 27/56Seed 11 (R3C5) needs two connections (in and out). Closed sides, left: wall, right: it would put the numbers in the order 12→11→1 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 28/56Linking R3C7 and R4C7 is impossible: it would put the numbers in the order 3→2→9 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 29/56Seed 2 (R3C7) needs two connections (in and out). Closed sides, right: edge of the board; down: it would put the numbers in the order 3→2→9 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 30/56R3C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 31/56Seed 9 (R4C7) needs two connections (in and out). Closed sides, right: edge of the board; up: it would put the numbers in the order 3→2→9 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 32/56Linking R4C1 and R4C2 is impossible: it would put the numbers in the order 1→2→3→12→11 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 33/56R4C1 needs two connections (in and out). Closed sides, left: edge of the board; right: it would put the numbers in the order 1→2→3→12→11 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 34/56R4C2 needs two connections (in and out). Closed sides, left: it would put the numbers in the order 1→2→3→12→11 on one stretch of path, but they must be visited in sequence, down: wall. So the path must go up and right from here.
- 35/56Linking R4C3 and R4C4 is impossible: it would put the numbers in the order 11→12→13→10 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 36/56Seed 13 (R4C3) needs two connections (in and out). Closed sides, up: R3C3 already has its two connections, right: it would put the numbers in the order 11→12→13→10 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 37/56Seed 10 (R4C4) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 11→12→10 on one stretch of path, but they must be visited in sequence, left: it would put the numbers in the order 11→12→13→10 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 38/56R4C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 39/56R4C6 needs two connections (in and out). Closed sides, up: R3C6 already has its two connections, left: R4C5 already has its two connections. So the path must go right and down from here.
- 40/56R5C5 needs two connections (in and out). Closed sides, up: R4C5 already has its two connections, down: wall. So the path must go left and right from here.
- 41/56R5C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 42/56R5C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 43/56R5C7 needs two connections (in and out). Closed sides, right: edge of the board; left: R5C6 already has its two connections. So the path must go up and down from here.
- 44/56Dot 8 at R6C7 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 45/56R6C6 needs two connections (in and out). Closed sides, up: R5C6 already has its two connections, right: R6C7 already has its two connections. So the path must go left and down from here.
- 46/56Dot 6 at R6C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 47/56R6C4 needs two connections (in and out). Closed sides, up: R5C4 already has its two connections, right: R6C5 already has its two connections. So the path must go left and down from here.
- 48/56R7C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 49/56R7C3 needs two connections (in and out). Closed sides, down: edge of the board; right: R7C4 already has its two connections. So the path must go up and left from here.
- 50/56Dot 5 at R6C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 51/56Dot 4 at R7C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 52/56R5C3 needs two connections (in and out). Closed sides, right: R5C4 already has its two connections, down: R6C3 already has its two connections. So the path must go up and left from here.
- 53/56Linking R5C1 and R5C2 is impossible: it would put the numbers in the order 1→2→3→14→13→12→11→10→9→8→7→6→5→4 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 54/56R5C1 needs two connections (in and out). Closed sides, left: edge of the board; right: it would put the numbers in the order 1→2→3→14→13→12→11→10→9→8→7→6→5→4 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 55/56R6C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 56/56Seed 14 (R5C2) needs two connections (in and out). Closed sides, up: wall, left: it would put the numbers in the order 1→2→3→14→13→12→11→10→9→8→7→6→5→4 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here. ✅ Solved!
Zip Normal answer as text
Everyday Grids Zip Hard Answer, Jan 21, 2026
7×7 grid- 0/51Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 51 logical steps, no guessing.
- 1/51R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/51R1C5 needs two connections (in and out). Closed sides, up: edge of the board; down: wall. So the path must go left and right from here.
- 3/51Seed 4 (R1C7) needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 4/51Dot 5 at R1C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 5/51R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 6/51R2C5 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 7/51R4C7 needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 8/51R5C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 9/51R5C7 needs two connections (in and out). Closed sides, right: edge of the board; up: wall. So the path must go left and down from here.
- 10/51R6C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 11/51R6C5 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 12/51R7C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 13/51R7C3 needs two connections (in and out). Closed sides, down: edge of the board; right: wall. So the path must go up and left from here.
- 14/51R7C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 15/51R6C2 needs two connections (in and out). Closed sides, left: wall, down: R7C2 already has its two connections. So the path must go up and right from here.
- 16/51R6C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 17/51R6C4 needs two connections (in and out). Closed sides, left: R6C3 already has its two connections, right: wall. So the path must go up and down from here.
- 18/51R7C4 needs two connections (in and out). Closed sides, down: edge of the board; left: wall. So the path must go up and right from here.
- 19/51R7C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 20/51R7C6 needs two connections (in and out). Closed sides, down: edge of the board; left: R7C5 already has its two connections. So the path must go up and right from here.
- 21/51R6C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 22/51Seed 2 (R6C7) needs two connections (in and out). Closed sides, right: edge of the board; left: R6C6 already has its two connections. So the path must go up and down from here.
- 23/51Linking R3C3 and R3C4 is impossible: it would connect seed 1 straight to seed 7. Mark that side closed.
- 24/51Linking R3C4 and R3C5 is impossible: it would put the numbers in the order 7→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 25/51Seed 7 (R3C4) needs two connections (in and out). Closed sides, left: it would connect seed 1 straight to seed 7, right: it would put the numbers in the order 7→3 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 26/51Dot 8 at R4C4 already has its one connection, it is the finish of the path, so the path cannot use its other side(s). Mark them as closed.
- 27/51R3C5 needs two connections (in and out). Closed sides, left: it would put the numbers in the order 7→3 on one stretch of path, but they must be visited in sequence, down: wall. So the path must go up and right from here.
- 28/51R4C3 needs two connections (in and out). Closed sides, left: wall, right: R4C4 already has its single connection (it is an end of the path). So the path must go up and down from here.
- 29/51Dot 1 at R3C3 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 30/51R4C5 needs two connections (in and out). Closed sides, up: wall, left: R4C4 already has its single connection (it is an end of the path). So the path must go right and down from here.
- 31/51R4C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 32/51R5C6 needs two connections (in and out). Closed sides, up: R4C6 already has its two connections, down: R6C6 already has its two connections. So the path must go left and right from here.
- 33/51R5C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 34/51R5C4 needs two connections (in and out). Closed sides, up: R4C4 already has its single connection (it is an end of the path), right: R5C5 already has its two connections. So the path must go left and down from here.
- 35/51R5C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 36/51Seed 6 (R5C2) needs two connections (in and out). Closed sides, left: wall, right: R5C3 already has its two connections. So the path must go up and down from here.
- 37/51Linking R1C4 and R2C4 is impossible: it would put the numbers in the order 4→5→7→8 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 38/51R1C4 needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 4→5→7→8 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 39/51R2C4 needs two connections (in and out). Closed sides, up: it would put the numbers in the order 4→5→7→8 on one stretch of path, but they must be visited in sequence, right: wall. So the path must go left and down from here.
- 40/51Linking R1C3 and R2C3 is impossible: it would put the numbers in the order 4→5→7→8 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 41/51R1C3 needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 4→5→7→8 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 42/51R1C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 43/51R2C2 needs two connections (in and out). Closed sides, up: R1C2 already has its two connections, left: wall. So the path must go right and down from here.
- 44/51Linking R2C6 and R3C6 is impossible: it would close a loop. Mark that side closed.
- 45/51Seed 3 (R2C6) needs two connections (in and out). Closed sides, up: R1C6 already has its two connections, down: it would close a loop. So the path must go left and right from here.
- 46/51R2C7 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 47/51R3C6 needs two connections (in and out). Closed sides, up: it would close a loop, down: R4C6 already has its two connections. So the path must go left and right from here.
- 48/51Linking R3C1 and R3C2 is impossible: it would put the numbers in the order 1→2→3→4→5→7→8 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 49/51R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: it would put the numbers in the order 1→2→3→4→5→7→8 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 50/51R4C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 51/51R3C2 needs two connections (in and out). Closed sides, left: it would put the numbers in the order 1→2→3→4→5→7→8 on one stretch of path, but they must be visited in sequence, right: R3C3 already has its single connection (it is an end of the path). So the path must go up and down from here. ✅ Solved!
Zip Hard answer as text
How to Solve Everyday Grids Zip: Quick Tips
- Start with cells that have only two open sides, the path is forced straight through them.
- Corners and dead-end pockets between walls must be entered and left immediately, so draw those links first.
- Never join two path pieces into a loop, and never connect numbers out of order.
- If a group of cells has only one way in, the path must use it, or that group would be left unvisited.