Everyday Grids Zip Answer Today: December 4, 2024

This page has the complete Everyday Grids Zip answers for December 4, 2024 (4 December 2024): the solved grids for both the Normal and Hard Zip levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Zip guide? It’s all below, and each Everyday Grids Zip solution is verified against the puzzle rules, so it matches the Dec 4, 2024 puzzle in the app exactly.
About Everyday Grids Zip
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Zip is one of them. Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can’t cross walls. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Zip puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Zip Answers and Solutions for December 4, 2024
Each level below shows the solved Zip grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Zip Normal Answer, Dec 4, 2024
7×7 grid- 0/55Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 55 logical steps, no guessing.
- 1/55R1C6 needs two connections (in and out). Closed sides, up: edge of the board; down: wall. So the path must go left and right from here.
- 2/55Seed 3 (R1C7) needs two connections (in and out). Closed sides, up/right: edge of the board. So the path must go left and down from here.
- 3/55R3C4 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 4/55R4C7 needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 5/55R5C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 6/55R5C2 needs two connections (in and out). Closed sides, left: wall, down: wall. So the path must go up and right from here.
- 7/55Seed 5 (R5C7) needs two connections (in and out). Closed sides, right: edge of the board; down: wall. So the path must go up and left from here.
- 8/55R6C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 9/55R6C2 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 10/55Seed 9 (R6C7) needs two connections (in and out). Closed sides, right: edge of the board; up: wall. So the path must go left and down from here.
- 11/55Seed 11 (R7C1) needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 12/55R7C3 needs two connections (in and out). Closed sides, down: edge of the board; left: wall. So the path must go up and right from here.
- 13/55R6C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 14/55R7C6 needs two connections (in and out). Closed sides, down: edge of the board; up: wall. So the path must go left and right from here.
- 15/55Linking R1C1 and R2C1 is impossible: it would connect seed 16 straight to seed 12. Mark that side closed.
- 16/55As the finish, seed 16 (R1C1) needs exactly one connection. Closed sides, up/left: edge of the board; down: it would connect seed 16 straight to seed 12. So the path must go right from here.
- 17/55Seed 12 (R2C1) needs two connections (in and out). Closed sides, left: edge of the board; up: it would connect seed 16 straight to seed 12. So the path must go right and down from here.
- 18/55Linking R1C2 and R2C2 is impossible: it would put the numbers in the order 16→15→13→12 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 19/55Seed 15 (R1C2) needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 16→15→13→12 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 20/55Linking R1C4 and R1C5 is impossible: it would put the numbers in the order 14→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 21/55Seed 14 (R1C4) needs two connections (in and out). Closed sides, up: edge of the board; right: it would put the numbers in the order 14→3 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 22/55R1C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 23/55R1C5 needs two connections (in and out). Closed sides, up: edge of the board; left: it would put the numbers in the order 14→3 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 24/55Linking R2C2 and R3C2 is impossible: it would put the numbers in the order 12→13→2 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 25/55Seed 13 (R2C2) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 16→15→13→12 on one stretch of path, but they must be visited in sequence, down: it would put the numbers in the order 12→13→2 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 26/55Linking R2C3 and R3C3 is impossible: it would put the numbers in the order 12→13→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 27/55R2C3 needs two connections (in and out). Closed sides, up: R1C3 already has its two connections, down: it would put the numbers in the order 12→13→1 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 28/55R2C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 29/55Linking R2C7 and R3C7 is impossible: it would put the numbers in the order 3→5→6 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 30/55R2C7 needs two connections (in and out). Closed sides, right: edge of the board; down: it would put the numbers in the order 3→5→6 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 31/55R3C7 needs two connections (in and out). Closed sides, right: edge of the board; up: it would put the numbers in the order 3→5→6 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 32/55Linking R2C5 and R2C6 is impossible: it would close a loop. Mark that side closed.
- 33/55R2C5 needs two connections (in and out). Closed sides, left: R2C4 already has its two connections, right: it would close a loop. So the path must go up and down from here.
- 34/55R3C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 35/55Seed 4 (R2C6) needs two connections (in and out). Closed sides, up: wall, left: it would close a loop. So the path must go right and down from here.
- 36/55R3C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 37/55R4C6 needs two connections (in and out). Closed sides, up: R3C6 already has its two connections, right: wall. So the path must go left and down from here.
- 38/55Dot 6 at R5C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 39/55Seed 8 (R5C5) needs two connections (in and out). Closed sides, right: R5C6 already has its two connections, down: wall. So the path must go up and left from here.
- 40/55Dot 7 at R4C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 41/55R6C6 needs two connections (in and out). Closed sides, up: R5C6 already has its two connections, down: wall. So the path must go left and right from here.
- 42/55Linking R3C1 and R3C2 is impossible: it would put the numbers in the order 16→15→14→13→12→2 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 43/55R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: it would put the numbers in the order 16→15→14→13→12→2 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 44/55R4C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 45/55Seed 2 (R3C2) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 12→13→2 on one stretch of path, but they must be visited in sequence, left: it would put the numbers in the order 16→15→14→13→12→2 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 46/55Dot 1 at R3C3 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 47/55R4C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 48/55R4C3 needs two connections (in and out). Closed sides, up: R3C3 already has its single connection (it is an end of the path), left: R4C2 already has its two connections. So the path must go right and down from here.
- 49/55R4C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 50/55R5C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 51/55R5C4 needs two connections (in and out). Closed sides, up: R4C4 already has its two connections, left: R5C3 already has its two connections. So the path must go right and down from here.
- 52/55Linking R6C4 and R7C4 is impossible: it would put the numbers in the order 1→2→3→4→5→6→7→8→11→12→13→14→15→16 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 53/55R6C4 needs two connections (in and out). Closed sides, left: R6C3 already has its two connections, down: it would put the numbers in the order 1→2→3→4→5→6→7→8→11→12→13→14→15→16 on one stretch of path, but they must be visited in sequence. So the path must go up and right from here.
- 54/55R6C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 55/55R7C4 needs two connections (in and out). Closed sides, down: edge of the board; up: it would put the numbers in the order 1→2→3→4→5→6→7→8→11→12→13→14→15→16 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here. ✅ Solved!
Zip Normal answer as text
Everyday Grids Zip Hard Answer, Dec 4, 2024
5×5 grid- 0/25Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 25 logical steps, no guessing.
- 1/25R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/25R1C2 needs two connections (in and out). Closed sides, up: edge of the board; right: wall. So the path must go left and down from here.
- 3/25R1C3 needs two connections (in and out). Closed sides, up: edge of the board; left: wall. So the path must go right and down from here.
- 4/25R3C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 5/25R2C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 6/25R3C2 needs two connections (in and out). Closed sides, left: wall, down: wall. So the path must go up and right from here.
- 7/25R2C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 8/25Seed 2 (R3C3) needs two connections (in and out). Closed sides, right: wall, down: wall. So the path must go up and left from here.
- 9/25R2C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 10/25R3C4 needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 11/25R3C5 needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 12/25R4C4 needs two connections (in and out). Closed sides, right: wall, down: wall. So the path must go up and left from here.
- 13/25R4C5 needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 14/25R5C4 needs two connections (in and out). Closed sides, down: edge of the board; up: wall. So the path must go left and right from here.
- 15/25Linking R4C1 and R5C1 is impossible: it would put the numbers in the order 2→4 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 16/25R4C1 needs two connections (in and out). Closed sides, left: edge of the board; down: it would put the numbers in the order 2→4 on one stretch of path, but they must be visited in sequence. So the path must go up and right from here.
- 17/25As the finish, seed 4 (R5C1) needs exactly one connection. Closed sides, down/left: edge of the board; up: it would put the numbers in the order 2→4 on one stretch of path, but they must be visited in sequence. So the path must go right from here.
- 18/25Linking R4C2 and R5C2 is impossible: it would put the numbers in the order 2→4 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 19/25R4C2 needs two connections (in and out). Closed sides, up: wall, down: it would put the numbers in the order 2→4 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 20/25Dot 3 at R4C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 21/25R5C2 needs two connections (in and out). Closed sides, down: edge of the board; up: it would put the numbers in the order 2→4 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 22/25Linking R1C4 and R2C4 is impossible: it would close a loop. Mark that side closed.
- 23/25R1C4 needs two connections (in and out). Closed sides, up: edge of the board; down: it would close a loop. So the path must go left and right from here.
- 24/25Dot 1 at R1C5 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 25/25R2C4 needs two connections (in and out). Closed sides, up: it would close a loop, left: R2C3 already has its two connections. So the path must go right and down from here. ✅ Solved!
Zip Hard answer as text
How to Solve Everyday Grids Zip: Quick Tips
- Start with cells that have only two open sides, the path is forced straight through them.
- Corners and dead-end pockets between walls must be entered and left immediately, so draw those links first.
- Never join two path pieces into a loop, and never connect numbers out of order.
- If a group of cells has only one way in, the path must use it, or that group would be left unvisited.