Everyday Grids Sums Answer Today: September 11, 2025

This page has the complete Everyday Grids Sums answers for September 11, 2025 (11 September 2025): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Sep 11, 2025 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for September 11, 2025
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Sep 11, 2025
6×6 grid- 0/10Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 10 logical steps, no guessing.
- 1/10Column 3 must total 2 using 8, 8, 2, 2, 1, 4. The ways to make 2 are: 2 (some using different copies of the same number). None uses R1C3, R2C3, R5C3, R6C3, so remove them.
- 2/10Row 5 must total 25 using 7, 6, 5, 4, 7. The only way to make 25 is 7 + 6 + 5 + 7. So keep R5C1, R5C2, R5C4, R5C6; remove R5C5.
- 3/10Purple area must total 20; the kept 6+7 = 13 so far, so the undecided numbers (1, 8, 5, 6) must add up to 7. The only way to make 7 is 1 + 6. So keep R6C2, R6C6; remove R6C4, R6C5.
- 4/10Peach area must total 15; the kept 7 = 7 so far, so the undecided numbers (3, 8, 7) must add up to 8. The only way to make 8 is 8. So keep R4C2; remove R4C1, R6C1.
- 5/10Column 1 must total 19; the kept 7 = 7 so far, so the undecided numbers (4, 8, 5) must add up to 12. The only way to make 12 is 4 + 8. So keep R1C1, R2C1; remove R3C1.
- 6/10Row 2 must total 13; the kept 8 = 8 so far, so the undecided numbers (8, 3, 1, 4) must add up to 5. The only way to make 5 is 1 + 4. So keep R2C5, R2C6; remove R2C2, R2C4.
- 7/10Column 4 must total 8; the kept 5 = 5 so far, so the undecided numbers (3, 1, 7) must add up to 3. The only way to make 3 is 3. So keep R1C4; remove R3C4, R4C4.
- 8/10Row 3 must total 2 using 5, 2, 6, 1. The only way to make 2 is 2. So keep R3C3; remove R3C2, R3C5, R3C6.
- 9/10Row 1 must total 18; the kept 4+3 = 7 so far, so the undecided numbers (6, 5, 8) must add up to 11. The only way to make 11 is 6 + 5. So keep R1C2, R1C5; remove R1C6.
- 10/10Row 4 must total 25; the kept 8 = 8 so far, so the undecided numbers (2, 9, 8) must add up to 17. The only way to make 17 is 9 + 8. So keep R4C5, R4C6; remove R4C3. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Sep 11, 2025
7×7 grid- 0/15Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 15 logical steps, no guessing.
- 1/15Row 4 must total 19 using 5, 9, 1, 1, 5, 2, 2. There are 5 ways to make 19. Every one uses R4C2, so keep it.
- 2/15Brown area must total 21; the kept 9 = 9 so far, so the undecided numbers (1, 1, 5, 7, 7, 7) must add up to 12. The ways to make 12 are: 5+7 (some using different copies of the same number). Every one uses R5C3, so keep it; none uses R4C3, R5C2, so remove them.
- 3/15Column 3 must total 14; the kept 5 = 5 so far, so the undecided numbers (1, 1, 7, 7, 6) must add up to 9. The ways to make 9 are: 1+1+7 (some using different copies of the same number). Every one uses R1C3, R2C3, so keep them; none uses R7C3, so remove it.
- 4/15Teal area must total 9; the kept 1+1 = 2 so far, so the undecided numbers (1, 8, 1, 5) must add up to 7. The only way to make 7 is 1 + 1 + 5. So keep R1C1, R2C1, R2C4; remove R1C2.
- 5/15Column 2 must total 25; the kept 9 = 9 so far, so the undecided numbers (3, 1, 7, 5) must add up to 16. The only way to make 16 is 3 + 1 + 7 + 5. So keep R2C2, R3C2, R6C2, R7C2.
- 6/15Row 2 must total 11; the kept 1+3+1+5 = 10 so far, so the undecided numbers (1, 4, 2) must add up to 1. The only way to make 1 is 1. So keep R2C5; remove R2C6, R2C7.
- 7/15Brown area must total 21; the kept 9+5+7 = 21 so far, so the undecided numbers (7, 7) must add up to 0. Nothing more is needed. Remove R5C4, R6C3.
- 8/15Column 4 must total 15; the kept 5 = 5 so far, so the undecided numbers (2, 2, 1, 4, 1) must add up to 10. The only way to make 10 is 2 + 2 + 1 + 4 + 1. So keep R1C4, R3C4, R4C4, R6C4, R7C4.
- 9/15Green area must total 26; the kept 5+1 = 6 so far, so the undecided numbers (4, 8, 6, 1, 2) must add up to 20. The only way to make 20 is 4 + 8 + 6 + 2. So keep R6C6, R7C1, R7C5, R7C7; remove R7C6.
- 10/15Row 5 must total 12; the kept 5 = 5 so far, so the undecided numbers (4, 5, 3, 9) must add up to 7. The only way to make 7 is 4 + 3. So keep R5C1, R5C6; remove R5C5, R5C7.
- 11/15Column 7 must total 13; the kept 2 = 2 so far, so the undecided numbers (7, 2, 2, 6) must add up to 11. The only way to make 11 is 7 + 2 + 2. So keep R1C7, R3C7, R4C7; remove R6C7.
- 12/15Column 1 must total 19; the kept 1+1+4+8 = 14 so far, so the undecided numbers (7, 5, 2) must add up to 5. The only way to make 5 is 5. So keep R4C1; remove R3C1, R6C1.
- 13/15Row 3 must total 13; the kept 1+2+2 = 5 so far, so the undecided numbers (7, 1, 5) must add up to 8. The only way to make 8 is 7 + 1. So keep R3C3, R3C5; remove R3C6.
- 14/15Column 5 must total 12; the kept 1+1+6 = 8 so far, so the undecided numbers (2, 5, 4) must add up to 4. The only way to make 4 is 4. So keep R6C5; remove R1C5, R4C5.
- 15/15Column 6 must total 10; the kept 3+4 = 7 so far, so the undecided numbers (1, 2) must add up to 3. The only way to make 3 is 1 + 2. So keep R1C6, R4C6. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.