Everyday Grids Sums Answer Today: September 10, 2026

This page has the complete Everyday Grids Sums answers for September 10, 2026 (10 September 2026): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Sep 10, 2026 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for September 10, 2026
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Sep 10, 2026
6×6 grid- 0/11Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 11 logical steps, no guessing.
- 1/11Column 3 must total 23 using 4, 7, 8, 4, 4, 5. The ways to make 23 are: 4+7+8+4, 7+8+4+4 (some using different copies of the same number). Every one uses R2C3, R3C3, so keep them; none uses R6C3, so remove it.
- 2/11Row 6 must total 22 using 5, 9, 9, 5, 3. The ways to make 22 are: 5+9+5+3 (some using different copies of the same number). Every one uses R6C1, R6C5, R6C6, so keep them.
- 3/11Column 5 must total 16; the kept 5 = 5 so far, so the undecided numbers (2, 7, 4, 3, 7) must add up to 11. The ways to make 11 are: 7+4, 4+7. Every one uses R3C5, so keep it; none uses R1C5, R4C5, so remove them.
- 4/11Row 3 must total 17; the kept 8+4 = 12 so far, so the undecided numbers (1, 9, 2, 2) must add up to 5. The only way to make 5 is 1 + 2 + 2. So keep R3C1, R3C4, R3C6; remove R3C2.
- 5/11Column 1 must total 14; the kept 1+5 = 6 so far, so the undecided numbers (5, 8, 5, 9) must add up to 8. The only way to make 8 is 8. So keep R2C1; remove R1C1, R4C1, R5C1.
- 6/11Row 1 must total 18 using 1, 4, 6, 8. The only way to make 18 is 4 + 6 + 8. So keep R1C3, R1C4, R1C6; remove R1C2.
- 7/11Row 4 must total 18 using 9, 4, 4, 9. The only way to make 18 is 9 + 9. So keep R4C2, R4C6; remove R4C3, R4C4.
- 8/11Column 2 must total 26; the kept 9 = 9 so far, so the undecided numbers (1, 7, 9) must add up to 17. The only way to make 17 is 1 + 7 + 9. So keep R2C2, R5C2, R6C2.
- 9/11Row 5 must total 24; the kept 7 = 7 so far, so the undecided numbers (4, 9, 7, 4) must add up to 17. The only way to make 17 is 4 + 9 + 4. So keep R5C3, R5C4, R5C6; remove R5C5.
- 10/11Column 4 must total 19; the kept 6+2+9 = 17 so far, so the undecided numbers (2, 9) must add up to 2. The only way to make 2 is 2. So keep R2C4; remove R6C4.
- 11/11Row 2 must total 25; the kept 8+1+7+2 = 18 so far, so the undecided numbers (7, 9) must add up to 7. The only way to make 7 is 7. So keep R2C5; remove R2C6. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Sep 10, 2026
7×7 grid- 0/15Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 15 logical steps, no guessing.
- 1/15Cream area must total 10 using 5, 2, 4, 4, 8, 4. The ways to make 10 are: 2+4+4, 2+8 (some using different copies of the same number). Every one uses R3C4, so keep it; none uses R3C3, so remove it.
- 2/15Row 3 must total 15; the kept 2 = 2 so far, so the undecided numbers (7, 8, 4, 4, 1) must add up to 13. The ways to make 13 are: 8+4+1 (some using different copies of the same number). Every one uses R3C2, R3C7, so keep them; none uses R3C1, so remove it.
- 3/15Brown area must total 14; the kept 8 = 8 so far, so the undecided numbers (7, 7, 6, 5) must add up to 6. The only way to make 6 is 6. So keep R5C1; remove R4C1, R4C2, R5C2.
- 4/15Row 4 must total 19 using 4, 2, 7, 7, 1. The only way to make 19 is 4 + 7 + 7 + 1. So keep R4C3, R4C5, R4C6, R4C7; remove R4C4.
- 5/15Column 7 must total 2; the kept 1+1 = 2 so far, so the undecided numbers (1, 2, 2, 6, 2) must add up to 0. Nothing more is needed. Remove R1C7, R2C7, R5C7, R6C7, R7C7.
- 6/15Column 2 must total 18; the kept 8 = 8 so far, so the undecided numbers (1, 7, 4, 3) must add up to 10. The only way to make 10 is 7 + 3. So keep R2C2, R7C2; remove R1C2, R6C2.
- 7/15Purple area must total 12; the kept 3 = 3 so far, so the undecided numbers (5, 7, 9, 5) must add up to 9. The only way to make 9 is 9. So keep R7C3; remove R6C1, R7C1, R7C4.
- 8/15Column 3 must total 18; the kept 4+9 = 13 so far, so the undecided numbers (5, 6, 8, 4) must add up to 5. The only way to make 5 is 5. So keep R1C3; remove R2C3, R5C3, R6C3.
- 9/15Row 2 must total 17; the kept 7 = 7 so far, so the undecided numbers (1, 9, 2, 2) must add up to 10. The only way to make 10 is 1 + 9. So keep R2C1, R2C4; remove R2C5, R2C6.
- 10/15Teal area must total 24; the kept 5+9 = 14 so far, so the undecided numbers (1, 9, 7) must add up to 10. The only way to make 10 is 1 + 9. So keep R1C4, R1C5; remove R1C6.
- 11/15Column 6 must total 18; the kept 7 = 7 so far, so the undecided numbers (4, 2, 1, 8) must add up to 11. The only way to make 11 is 2 + 1 + 8. So keep R5C6, R6C6, R7C6; remove R3C6.
- 12/15Row 5 must total 10; the kept 6+2 = 8 so far, so the undecided numbers (2, 4) must add up to 2. The only way to make 2 is 2. So keep R5C4; remove R5C5.
- 13/15Row 6 must total 6; the kept 1 = 1 so far, so the undecided numbers (1, 5) must add up to 5. The only way to make 5 is 5. So keep R6C5; remove R6C4.
- 14/15Column 5 must total 25; the kept 9+7+5 = 21 so far, so the undecided numbers (4, 5) must add up to 4. The only way to make 4 is 4. So keep R3C5; remove R7C5.
- 15/15Row 1 must total 22; the kept 5+1+9 = 15 so far, so the undecided numbers (7) must add up to 7. The only way to make 7 is 7. So keep R1C1. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.