Everyday Grids Sums Answer Today: October 7, 2025

This page has the complete Everyday Grids Sums answers for October 7, 2025 (7 October 2025): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Oct 7, 2025 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for October 7, 2025
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Oct 7, 2025
6×6 grid- 0/12Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 12 logical steps, no guessing.
- 1/12Row 6 must total 15 using 7, 7, 5, 6, 2, 5. The ways to make 15 are: 7+6+2 (some using different copies of the same number). Every one uses R6C4, R6C5, so keep them; none uses R6C3, R6C6, so remove them.
- 2/12Purple area must total 5; the kept 2 = 2 so far, so the undecided numbers (3) must add up to 3. The only way to make 3 is 3. So keep R5C6.
- 3/12Column 2 must total 19 using 2, 1, 3, 4, 5, 7. The ways to make 19 are: 2+1+4+5+7, 3+4+5+7. Every one uses R4C2, R5C2, R6C2, so keep them.
- 4/12Row 5 must total 16; the kept 5+3 = 8 so far, so the undecided numbers (3, 7, 2, 8) must add up to 8. The only way to make 8 is 8. So keep R5C5; remove R5C1, R5C3, R5C4.
- 5/12Column 5 must total 19; the kept 8+2 = 10 so far, so the undecided numbers (6, 4, 3, 7) must add up to 9. The only way to make 9 is 6 + 3. So keep R1C5, R3C5; remove R2C5, R4C5.
- 6/12Row 1 must total 6; the kept 6 = 6 so far, so the undecided numbers (4, 2, 2, 1, 9) must add up to 0. Nothing more is needed. Remove R1C1, R1C2, R1C3, R1C4, R1C6.
- 7/12Row 2 must total 12 using 3, 1, 9, 1, 6. The only way to make 12 is 3 + 9. So keep R2C1, R2C3; remove R2C2, R2C4, R2C6.
- 8/12Row 3 must total 7; the kept 3 = 3 so far, so the undecided numbers (8, 3, 6, 1, 6) must add up to 4. The only way to make 4 is 3 + 1. So keep R3C2, R3C4; remove R3C1, R3C3, R3C6.
- 9/12Column 1 must total 7; the kept 3 = 3 so far, so the undecided numbers (4, 7) must add up to 4. The only way to make 4 is 4. So keep R4C1; remove R6C1.
- 10/12Column 3 must total 9; the kept 9 = 9 so far, so the undecided numbers (9) must add up to 0. Nothing more is needed. Remove R4C3.
- 11/12Column 4 must total 7; the kept 1+6 = 7 so far, so the undecided numbers (9) must add up to 0. Nothing more is needed. Remove R4C4.
- 12/12Row 4 must total 17; the kept 4+4 = 8 so far, so the undecided numbers (9) must add up to 9. The only way to make 9 is 9. So keep R4C6. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Oct 7, 2025
7×7 grid- 0/16Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 16 logical steps, no guessing.
- 1/16Yellow area must total 9 using 3, 1, 7, 7, 4, 9, 2. The ways to make 9 are: 3+4+2, 7+2, 9 (some using different copies of the same number). None uses R1C7, so remove it.
- 2/16Row 1 must total 20 using 1, 4, 5, 8, 3, 3. The ways to make 20 are: 1+5+8+3+3, 4+5+8+3 (some using different copies of the same number). Every one uses R1C3, R1C4, so keep them.
- 3/16Column 4 must total 20; the kept 8 = 8 so far, so the undecided numbers (4, 7, 1, 3, 4, 6) must add up to 12. The ways to make 12 are: 4+7+1, 4+1+3+4, 7+1+4. Every one uses R4C4, so keep it; none uses R7C4, so remove it.
- 4/16Brown area must total 22 using 3, 6, 4, 5, 7, 3. The ways to make 22 are: 3+4+5+7+3, 6+4+5+7. Every one uses R6C4, R6C5, R7C5, so keep them.
- 5/16Row 6 must total 19; the kept 4+5 = 9 so far, so the undecided numbers (4, 8, 6, 8, 5) must add up to 10. The only way to make 10 is 4 + 6. So keep R6C1, R6C3; remove R6C2, R6C6, R6C7.
- 6/16Column 5 must total 18; the kept 5+7 = 12 so far, so the undecided numbers (3, 7, 9, 2, 6) must add up to 6. The only way to make 6 is 6. So keep R5C5; remove R1C5, R2C5, R3C5, R4C5.
- 7/16Peach area must total 30; the kept 6 = 6 so far, so the undecided numbers (8, 8, 5, 3) must add up to 24. The only way to make 24 is 8 + 8 + 5 + 3. So keep R4C2, R5C1, R5C2, R5C3.
- 8/16Column 3 must total 14; the kept 5+3+6 = 14 so far, so the undecided numbers (6, 7, 3, 1) must add up to 0. Nothing more is needed. Remove R2C3, R3C3, R4C3, R7C3.
- 9/16Row 7 must total 13; the kept 7 = 7 so far, so the undecided numbers (1, 4, 3, 5) must add up to 6. The only way to make 6 is 1 + 5. So keep R7C1, R7C7; remove R7C2, R7C6.
- 10/16Column 1 must total 20; the kept 8+4+1 = 13 so far, so the undecided numbers (1, 7, 3, 9) must add up to 7. The only way to make 7 is 7. So keep R2C1; remove R1C1, R3C1, R4C1.
- 11/16Row 5 must total 22; the kept 8+5+3+6 = 22 so far, so the undecided numbers (3, 6, 4) must add up to 0. Nothing more is needed. Remove R5C4, R5C6, R5C7.
- 12/16Column 6 must total 8 using 3, 7, 2, 3. The only way to make 8 is 3 + 2 + 3. So keep R1C6, R3C6, R4C6; remove R2C6.
- 13/16Row 3 must total 13; the kept 2 = 2 so far, so the undecided numbers (6, 7, 4) must add up to 11. The only way to make 11 is 7 + 4. So keep R3C4, R3C7; remove R3C2.
- 14/16Column 2 must total 19; the kept 8+5 = 13 so far, so the undecided numbers (4, 2) must add up to 6. The only way to make 6 is 4 + 2. So keep R1C2, R2C2.
- 15/16Column 7 must total 18; the kept 4+5 = 9 so far, so the undecided numbers (4, 5) must add up to 9. The only way to make 9 is 4 + 5. So keep R2C7, R4C7.
- 16/16Row 2 must total 13; the kept 7+2+4 = 13 so far, so the undecided numbers (4) must add up to 0. Nothing more is needed. Remove R2C4. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.