Everyday Grids Sums Answer Today: April 22, 2025

This page has the complete Everyday Grids Sums answers for April 22, 2025 (22 April 2025): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Apr 22, 2025 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for April 22, 2025
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Apr 22, 2025
5×5 grid- 0/7Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 7 logical steps, no guessing.
- 1/7Purple area must total 21 using 1, 3, 5, 7, 1, 5. The ways to make 21 are: 1+3+5+7+5, 3+5+7+1+5. Every one uses R3C2, R3C3, R3C4, R5C1, so keep them.
- 2/7Row 5 must total 11; the kept 5 = 5 so far, so the undecided numbers (2, 3, 7, 1) must add up to 6. The only way to make 6 is 2 + 3 + 1. So keep R5C2, R5C3, R5C5; remove R5C4.
- 3/7Column 5 must total 7; the kept 1 = 1 so far, so the undecided numbers (4, 1, 3, 5) must add up to 6. The only way to make 6 is 1 + 5. So keep R2C5, R4C5; remove R1C5, R3C5.
- 4/7Row 1 must total 13 using 3, 2, 4, 4. The only way to make 13 is 3 + 2 + 4 + 4. So keep R1C1, R1C2, R1C3, R1C4.
- 5/7Row 2 must total 12; the kept 1 = 1 so far, so the undecided numbers (2, 5, 9, 1) must add up to 11. The only way to make 11 is 2 + 9. So keep R2C1, R2C3; remove R2C2, R2C4.
- 6/7Row 4 must total 15; the kept 5 = 5 so far, so the undecided numbers (1, 3, 8, 6) must add up to 10. The only way to make 10 is 1 + 3 + 6. So keep R4C1, R4C2, R4C4; remove R4C3.
- 7/7Row 3 must total 15; the kept 3+5+7 = 15 so far, so the undecided numbers (1) must add up to 0. Nothing more is needed. Remove R3C1. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Apr 22, 2025
7×7 grid- 0/21Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 21 logical steps, no guessing.
- 1/21Purple area must total 8 using 1, 4, 2, 5, 5, 1. There are 5 ways to make 8. Every one uses R5C6, so keep it.
- 2/21Row 5 must total 11; the kept 2 = 2 so far, so the undecided numbers (8, 7, 4, 1, 5, 5) must add up to 9. The ways to make 9 are: 8+1, 4+5 (some using different copies of the same number). None uses R5C2, so remove it.
- 3/21Brown area must total 18 using 7, 4, 3, 6, 1. The only way to make 18 is 7 + 4 + 6 + 1. So keep R4C3, R5C3, R7C1, R7C2; remove R6C2.
- 4/21Column 2 must total 15; the kept 1 = 1 so far, so the undecided numbers (4, 1, 9, 8) must add up to 14. The only way to make 14 is 4 + 1 + 9. So keep R1C2, R2C2, R3C2; remove R4C2.
- 5/21Row 5 must total 11; the kept 4+2 = 6 so far, so the undecided numbers (8, 1, 5, 5) must add up to 5. The ways to make 5 are: 5 (some using different copies of the same number). None uses R5C1, R5C4, so remove them.
- 6/21Peach area must total 9 using 4, 5, 8, 4. The ways to make 9 are: 4+5, 5+4. Every one uses R5C5, so keep it; none uses R6C3, so remove it.
- 7/21Row 5 must total 11; the kept 4+5+2 = 11 so far, so the undecided numbers (5) must add up to 0. Nothing more is needed. Remove R5C7.
- 8/21Row 6 must total 18 using 9, 4, 3, 2, 5. The ways to make 18 are: 9+4+3+2, 9+4+5. Every one uses R6C1, R6C4, so keep them.
- 9/21Peach area must total 9; the kept 5+4 = 9 so far, so the undecided numbers (4) must add up to 0. Nothing more is needed. Remove R4C4.
- 10/21Row 4 must total 12; the kept 7 = 7 so far, so the undecided numbers (8, 1, 4, 4) must add up to 5. The ways to make 5 are: 1+4 (some using different copies of the same number). Every one uses R4C5, so keep it; none uses R4C1, so remove it.
- 11/21Column 1 must total 29; the kept 9+6 = 15 so far, so the undecided numbers (7, 7, 6) must add up to 14. The only way to make 14 is 7 + 7. So keep R1C1, R2C1; remove R3C1.
- 12/21Row 1 must total 18; the kept 7+4 = 11 so far, so the undecided numbers (6, 3, 7, 2, 1) must add up to 7. The ways to make 7 are: 6+1, 7. None uses R1C4, R1C6, so remove them.
- 13/21Column 4 must total 8; the kept 4 = 4 so far, so the undecided numbers (3, 1, 2) must add up to 4. The only way to make 4 is 3 + 1. So keep R2C4, R3C4; remove R7C4.
- 14/21Column 6 must total 19; the kept 2 = 2 so far, so the undecided numbers (7, 4, 4, 2, 2) must add up to 17. The ways to make 17 are: 7+4+4+2 (some using different copies of the same number). Every one uses R2C6, R3C6, R4C6, so keep them.
- 15/21Row 2 must total 19; the kept 7+1+3+7 = 18 so far, so the undecided numbers (5, 8, 1) must add up to 1. The only way to make 1 is 1. So keep R2C7; remove R2C3, R2C5.
- 16/21Row 3 must total 21; the kept 9+1+4 = 14 so far, so the undecided numbers (8, 4, 3) must add up to 7. The only way to make 7 is 4 + 3. So keep R3C5, R3C7; remove R3C3.
- 17/21Column 7 must total 6; the kept 1+3 = 4 so far, so the undecided numbers (1, 4, 5, 1) must add up to 2. The only way to make 2 is 1 + 1. So keep R1C7, R7C7; remove R4C7, R6C7.
- 18/21Row 1 must total 18; the kept 7+4+1 = 12 so far, so the undecided numbers (6, 7) must add up to 6. The only way to make 6 is 6. So keep R1C3; remove R1C5.
- 19/21Row 6 must total 18; the kept 9+4 = 13 so far, so the undecided numbers (3, 2) must add up to 5. The only way to make 5 is 3 + 2. So keep R6C5, R6C6.
- 20/21Column 3 must total 19; the kept 6+7+4 = 17 so far, so the undecided numbers (2) must add up to 2. The only way to make 2 is 2. So keep R7C3.
- 21/21Row 7 must total 14; the kept 6+1+2+1 = 10 so far, so the undecided numbers (4, 2) must add up to 4. The only way to make 4 is 4. So keep R7C5; remove R7C6. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.