TOP NEW / POPULAR GAMES
Everyday Grids Zip Answer Today: May 9, 2026
📅This page is for May 9, 2026. Playing a different day? Scroll down to More Days and pick your date, or open the all-days calendar at the bottom. New puzzles unlock at midnight in your own time zone, so if it is still the previous day where you live, use the previous day link.
This page has the complete Everyday Grids Zip answers for May 9, 2026 (9 May 2026): the solved grids for both the Normal and Hard Zip levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Zip guide? It’s all below, and each Everyday Grids Zip solution is verified against the puzzle rules, so it matches the May 9, 2026 puzzle in the app exactly.
About Everyday Grids Zip
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Zip is one of them. Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can’t cross walls. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Zip puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Zip Answers and Solutions for May 9, 2026
Each level below shows the solved Zip grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Zip Normal Answer, May 9, 2026
7×7 grid✅ Solved Normal grid
- 0/57Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 57 logical steps, no guessing.
- 1/57Seed 10 (R1C1) needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/57R1C4 needs two connections (in and out). Closed sides, up: edge of the board; right: wall. So the path must go left and down from here.
- 3/57R1C5 needs two connections (in and out). Closed sides, up: edge of the board; left: wall. So the path must go right and down from here.
- 4/57R2C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 5/57Seed 12 (R2C4) needs two connections (in and out). Closed sides, left: wall, right: wall. So the path must go up and down from here.
- 6/57Seed 13 (R3C5) needs two connections (in and out). Closed sides, right: wall, down: wall. So the path must go up and left from here.
- 7/57R2C5 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 8/57R3C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 9/57R4C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 10/57Dot 9 at R3C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 11/57R4C4 needs two connections (in and out). Closed sides, up: wall, left: wall. So the path must go right and down from here.
- 12/57R5C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 13/57Seed 8 (R7C1) needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 14/57R6C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 15/57R7C2 needs two connections (in and out). Closed sides, down: edge of the board; right: wall. So the path must go up and left from here.
- 16/57R7C3 needs two connections (in and out). Closed sides, down: edge of the board; left: wall. So the path must go up and right from here.
- 17/57R7C5 needs two connections (in and out). Closed sides, down: edge of the board; up: wall. So the path must go left and right from here.
- 18/57R7C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 19/57R7C7 needs two connections (in and out). Closed sides, down/right: edge of the board. So the path must go up and left from here.
- 20/57R7C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 21/57Linking R1C2 and R1C3 is impossible: it would put the numbers in the order 8→9→10→12→13→14 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 22/57R1C2 needs two connections (in and out). Closed sides, up: edge of the board; right: it would put the numbers in the order 8→9→10→12→13→14 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 23/57R1C3 needs two connections (in and out). Closed sides, up: edge of the board; left: it would put the numbers in the order 8→9→10→12→13→14 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 24/57Linking R1C6 and R2C6 is impossible: it would put the numbers in the order 12→13→14→5 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 25/57Seed 14 (R1C6) needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 12→13→14→5 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 26/57Dot 15 at R1C7 already has its one connection, it is the finish of the path, so the path cannot use its other side(s). Mark them as closed.
- 27/57Seed 5 (R2C6) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 12→13→14→5 on one stretch of path, but they must be visited in sequence, left: R2C5 already has its two connections. So the path must go right and down from here.
- 28/57R2C7 needs two connections (in and out). Closed sides, right: edge of the board; up: R1C7 already has its single connection (it is an end of the path). So the path must go left and down from here.
- 29/57Linking R2C2 and R3C2 is impossible: it would put the numbers in the order 8→9→10→11→7 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 30/57Seed 11 (R2C2) needs two connections (in and out). Closed sides, left: wall, down: it would put the numbers in the order 8→9→10→11→7 on one stretch of path, but they must be visited in sequence. So the path must go up and right from here.
- 31/57R2C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 32/57Seed 7 (R3C2) needs two connections (in and out). Closed sides, up: it would put the numbers in the order 8→9→10→11→7 on one stretch of path, but they must be visited in sequence, left: R3C1 already has its two connections. So the path must go right and down from here.
- 33/57R3C3 needs two connections (in and out). Closed sides, up: R2C3 already has its two connections, right: R3C4 already has its two connections. So the path must go left and down from here.
- 34/57Linking R3C6 and R3C7 is impossible: it would close a loop. Mark that side closed.
- 35/57R3C6 needs two connections (in and out). Closed sides, left: wall, right: it would close a loop. So the path must go up and down from here.
- 36/57Seed 4 (R3C7) needs two connections (in and out). Closed sides, right: edge of the board; left: it would close a loop. So the path must go up and down from here.
- 37/57Linking R4C2 and R4C3 is impossible: it would close a loop. Mark that side closed.
- 38/57R4C2 needs two connections (in and out). Closed sides, left: wall, right: it would close a loop. So the path must go up and down from here.
- 39/57R4C3 needs two connections (in and out). Closed sides, left: it would close a loop, right: wall. So the path must go up and down from here.
- 40/57Linking R4C6 and R4C7 is impossible: it would close a loop. Mark that side closed.
- 41/57R4C7 needs two connections (in and out). Closed sides, right: edge of the board; left: it would close a loop. So the path must go up and down from here.
- 42/57Linking R5C2 and R5C3 is impossible: it would close a loop. Mark that side closed.
- 43/57R5C2 needs two connections (in and out). Closed sides, left: wall, right: it would close a loop. So the path must go up and down from here.
- 44/57R6C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 45/57Seed 6 (R5C3) needs two connections (in and out). Closed sides, left: it would close a loop, down: wall. So the path must go up and right from here.
- 46/57R5C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 47/57R6C3 needs two connections (in and out). Closed sides, up: wall, left: R6C2 already has its two connections. So the path must go right and down from here.
- 48/57Dot 1 at R6C4 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 49/57Seed 3 (R6C5) needs two connections (in and out). Closed sides, left: R6C4 already has its single connection (it is an end of the path), down: wall. So the path must go up and right from here.
- 50/57Linking R4C5 and R5C5 is impossible: it would put the numbers in the order 15→14→13→12→11→10→9→8→7→6→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 51/57R4C5 needs two connections (in and out). Closed sides, up: wall, down: it would put the numbers in the order 15→14→13→12→11→10→9→8→7→6→3 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 52/57R4C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 53/57R5C5 needs two connections (in and out). Closed sides, up: it would put the numbers in the order 15→14→13→12→11→10→9→8→7→6→3 on one stretch of path, but they must be visited in sequence, left: R5C4 already has its two connections. So the path must go right and down from here.
- 54/57Linking R5C6 and R6C6 is impossible: it would close a loop. Mark that side closed.
- 55/57R5C6 needs two connections (in and out). Closed sides, up: R4C6 already has its two connections, down: it would close a loop. So the path must go left and right from here.
- 56/57R5C7 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 57/57R6C6 needs two connections (in and out). Closed sides, up: it would close a loop, down: R7C6 already has its two connections. So the path must go left and right from here. ✅ Solved!
Zip Normal answer as text
Start at 1 (R6C4) and move: ← ↓ → → → → ↑ ← ← ↑ → → ↑ ↑ ↑ ← ↓ ↓ ← ← ↓ ← ↑ ↑ ← ↓ ↓ ↓ ↓ ← ↑ ↑ ↑ ↑ ↑ ↑ → ↓ → ↑ → ↓ ↓ → ↑ ↑ → →, finishing on 15.
Everyday Grids Zip Hard Answer, May 9, 2026
7×7 grid✅ Solved Hard grid
- 0/67Start at 🌻 1. A cell in the middle of the path needs exactly two connections (in and out); the start and finish need one. Walls and the board edge close sides off. Tap Start to follow all 67 logical steps, no guessing.
- 1/67R1C1 needs two connections (in and out). Closed sides, up/left: edge of the board. So the path must go right and down from here.
- 2/67R1C2 needs two connections (in and out). Closed sides, up: edge of the board; down: wall. So the path must go left and right from here.
- 3/67R2C1 needs two connections (in and out). Closed sides, left: edge of the board; down: wall. So the path must go up and right from here.
- 4/67R2C2 needs two connections (in and out). Closed sides, up: wall, right: wall. So the path must go left and down from here.
- 5/67R3C1 needs two connections (in and out). Closed sides, left: edge of the board; up: wall. So the path must go right and down from here.
- 6/67R3C2 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 7/67R3C4 needs two connections (in and out). Closed sides, up: wall, right: wall. So the path must go left and down from here.
- 8/67R4C1 needs two connections (in and out). Closed sides, left: edge of the board; right: wall. So the path must go up and down from here.
- 9/67R4C2 needs two connections (in and out). Closed sides, up: R3C2 already has its two connections, left: wall. So the path must go right and down from here.
- 10/67R6C7 needs two connections (in and out). Closed sides, right: edge of the board; left: wall. So the path must go up and down from here.
- 11/67R7C1 needs two connections (in and out). Closed sides, down/left: edge of the board. So the path must go up and right from here.
- 12/67R7C7 needs two connections (in and out). Closed sides, down/right: edge of the board. So the path must go up and left from here.
- 13/67Check: if the path did NOT use the link R2C3–R2C4, then after 1 forced move the numbers 7→3 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 14/67Check: if the path did NOT use the link R3C7–R4C7, then after 2 forced moves the numbers 2→5 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 15/67Check: if the path used the link R5C2–R5C3, then after 4 forced moves the numbers 4→7 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 16/67Check: if the path did NOT use the link R1C4–R1C5, then after 5 forced moves the numbers 7→3 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 17/67Check: if the path used the link R6C2–R7C2, then after 6 forced moves the path would close into a loop. (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 18/67R7C2 needs two connections (in and out). Closed sides, down: edge of the board; up: leads to a contradiction. So the path must go left and right from here.
- 19/67Check: if the path did NOT use the link R6C2–R6C3, then after 3 forced moves seed 7 (R5C1) would become a dead end (not enough ways in and out). (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 20/67Check: if the path did NOT use the link R2C6–R2C7, then after 7 forced moves the numbers 8→5 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 21/67Check: if the path used the link R2C6–R3C6, then after 10 forced moves the numbers 3→1 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 22/67Check: if the path used the link R3C5–R4C5, then after 8 forced moves R2C5 would become a dead end (not enough ways in and out). (The dashed red line shows that imagined route.) That can't happen, so the path does not use this link.
- 23/67Check: if the path did NOT use the link R3C6–R4C6, then after 8 forced moves R2C5 would become a dead end (not enough ways in and out). (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 24/67Check: if the path did NOT use the link R1C6–R1C7, then after 11 forced moves the numbers 3→1 would be visited out of order. (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 25/67Dot 8 at R1C7 already has its one connection, it is the finish of the path, so the path cannot use its other side(s). Mark them as closed.
- 26/67R2C7 needs two connections (in and out). Closed sides, right: edge of the board; up: R1C7 already has its single connection (it is an end of the path). So the path must go left and down from here.
- 27/67R3C7 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 28/67R3C6 needs two connections (in and out). Closed sides, up: leads to a contradiction, right: R3C7 already has its two connections. So the path must go left and down from here.
- 29/67Dot 1 at R3C5 already has its one connection, it is the start of the path, so the path cannot use its other side(s). Mark them as closed.
- 30/67Check: if the path did NOT use the link R1C3–R1C4, then after 7 forced moves R1C6 would become a dead end (not enough ways in and out). (The dashed red line shows that imagined route.) That can't happen, so the path must use this link.
- 31/67R1C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 32/67R1C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 33/67R2C3 needs two connections (in and out). Closed sides, up: R1C3 already has its two connections, left: wall. So the path must go right and down from here.
- 34/67R3C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 35/67R2C4 needs two connections (in and out). Closed sides, up: R1C4 already has its two connections, down: wall. So the path must go left and right from here.
- 36/67Linking R1C5 and R2C5 is impossible: it would put the numbers in the order 7→3 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 37/67R1C5 needs two connections (in and out). Closed sides, up: edge of the board; down: it would put the numbers in the order 7→3 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 38/67R1C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 39/67R2C5 needs two connections (in and out). Closed sides, up: it would put the numbers in the order 7→3 on one stretch of path, but they must be visited in sequence, down: R3C5 already has its single connection (it is an end of the path). So the path must go left and right from here.
- 40/67Linking R4C7 and R5C7 is impossible: it would put the numbers in the order 3→5 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 41/67R4C7 needs two connections (in and out). Closed sides, right: edge of the board; down: it would put the numbers in the order 3→5 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 42/67Dot 2 at R4C6 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 43/67R4C5 needs two connections (in and out). Closed sides, up: leads to a contradiction, right: R4C6 already has its two connections. So the path must go left and down from here.
- 44/67Dot 3 at R4C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 45/67R4C3 needs two connections (in and out). Closed sides, up: R3C3 already has its two connections, right: R4C4 already has its two connections. So the path must go left and down from here.
- 46/67R5C7 needs two connections (in and out). Closed sides, right: edge of the board; up: it would put the numbers in the order 3→5 on one stretch of path, but they must be visited in sequence. So the path must go left and down from here.
- 47/67Linking R5C5 and R5C6 is impossible: it would put the numbers in the order 1→2→3→5 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 48/67R5C6 needs two connections (in and out). Closed sides, up: R4C6 already has its two connections, left: it would put the numbers in the order 1→2→3→5 on one stretch of path, but they must be visited in sequence. So the path must go right and down from here.
- 49/67Linking R6C6 and R7C6 is impossible: it would close a loop. Mark that side closed.
- 50/67R6C6 needs two connections (in and out). Closed sides, right: wall, down: it would close a loop. So the path must go up and left from here.
- 51/67Seed 5 (R7C6) needs two connections (in and out). Closed sides, down: edge of the board; up: it would close a loop. So the path must go left and right from here.
- 52/67Linking R5C5 and R6C5 is impossible: it would put the numbers in the order 1→2→3→5→6 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 53/67R5C5 needs two connections (in and out). Closed sides, right: it would put the numbers in the order 1→2→3→5 on one stretch of path, but they must be visited in sequence, down: it would put the numbers in the order 1→2→3→5→6 on one stretch of path, but they must be visited in sequence. So the path must go up and left from here.
- 54/67Linking R6C5 and R7C5 is impossible: it would close a loop. Mark that side closed.
- 55/67R6C5 needs two connections (in and out). Closed sides, up: it would put the numbers in the order 1→2→3→5→6 on one stretch of path, but they must be visited in sequence, down: it would close a loop. So the path must go left and right from here.
- 56/67Seed 6 (R7C5) needs two connections (in and out). Closed sides, down: edge of the board; up: it would close a loop. So the path must go left and right from here.
- 57/67Linking R5C4 and R6C4 is impossible: it would put the numbers in the order 1→2→3→5→6 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 58/67R5C4 needs two connections (in and out). Closed sides, up: R4C4 already has its two connections, down: it would put the numbers in the order 1→2→3→5→6 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 59/67R5C3 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 60/67Linking R5C1 and R5C2 is impossible: it would put the numbers in the order 8→7→3→2→1 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 61/67Seed 7 (R5C1) needs two connections (in and out). Closed sides, left: edge of the board; right: it would put the numbers in the order 8→7→3→2→1 on one stretch of path, but they must be visited in sequence. So the path must go up and down from here.
- 62/67R6C1 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 63/67R5C2 needs two connections (in and out). Closed sides, left: it would put the numbers in the order 8→7→3→2→1 on one stretch of path, but they must be visited in sequence, right: leads to a contradiction. So the path must go up and down from here.
- 64/67Linking R6C3 and R7C3 is impossible: it would put the numbers in the order 1→2→3→4→7→8 on one stretch of path, but they must be visited in sequence. Mark that side closed.
- 65/67R6C3 needs two connections (in and out). Closed sides, up: R5C3 already has its two connections, down: it would put the numbers in the order 1→2→3→4→7→8 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here.
- 66/67R6C4 already has both of its connections, so the path cannot use its other side(s). Mark them as closed.
- 67/67R7C3 needs two connections (in and out). Closed sides, down: edge of the board; up: it would put the numbers in the order 1→2→3→4→7→8 on one stretch of path, but they must be visited in sequence. So the path must go left and right from here. ✅ Solved!
Zip Hard answer as text
Start at 1 (R3C5) and move: → ↓ → ↑ ↑ ← ← ← ← ↓ → ↓ → ↓ ← ← ↑ ← ↓ ↓ → → → → ↑ → ↓ ↓ ← ← ← ← ← ← ↑ ↑ ↑ ↑ → ↑ ← ↑ → → → → → →, finishing on 8.
How to Solve Everyday Grids Zip: Quick Tips
Want to beat tomorrow’s Everyday Grids Zip without help? These are the logical moves our step by step solutions use most often:
- Start with cells that have only two open sides, the path is forced straight through them.
- Corners and dead-end pockets between walls must be entered and left immediately, so draw those links first.
- Never join two path pieces into a loop, and never connect numbers out of order.
- If a group of cells has only one way in, the path must use it, or that group would be left unvisited.
Other Everyday Grids Answers for May 9, 2026
More Days: Everyday Grids Zip Answers by Date
Everyday Grids Zip FAQ
How do you play Everyday Grids Zip?
Draw one continuous path through every cell exactly once, starting at 1 and visiting the numbered seeds in order. The path can't cross walls.
Is there a Normal and a Hard Zip puzzle every day?
Yes. Everyday Grids releases a Normal and a Hard Zip level every day, and both answers and solutions are on this page.
Are these Everyday Grids Zip answers for May 9, 2026 correct?
Yes. Each grid is solved with pure logic step by step and checked against the puzzle rules, so it matches the one valid solution.
My Zip puzzle looks different. What should I do?
Check the date first: this page is for May 9, 2026. Use the date links under More Days to find your day, and if it still looks different, leave a comment so we can check it.
💛
Thanks for solving with us!
Come back tomorrow for a fresh set of grids. Is your puzzle different from the one on this page, are you stuck on a step, or did you spot a mistake? Tell us in the comments with the game, the level (Normal or Hard) and your date, and share any suggestions too. We read every comment and use it to improve these answers.
✍️ Leave a comment