Everyday Grids Sums Answer Today: March 29, 2026

This page has the complete Everyday Grids Sums answers for March 29, 2026 (29 March 2026): the solved grids for both the Normal and Hard Sums levels, plus a full solution walkthrough with a step by step explanation of every move. Need a quick cheat to check your grid, a hint to get unstuck, or a complete Sums guide? It’s all below, and each Everyday Grids Sums solution is verified against the puzzle rules, so it matches the Mar 29, 2026 puzzle in the app exactly.
About Everyday Grids Sums
Everyday Grids is a relaxing daily logic-puzzle game by Fanatee with seven different grids: Zip, Gems, Lotus, Panda, Libra, Sums and Hashi. Everyday Grids Sums is one of them. Remove numbers so the ones left match every row total, column total and colour-area total. Every level can be solved with pure logic, with no guessing and no luck, and a brand-new Normal and Hard Sums puzzle is released every day. The game is free to download on Android and iPhone.
Everyday Grids Sums Answers and Solutions for March 29, 2026
Each level below shows the solved Sums grid first, so you can copy the answer straight away. If you’d rather learn how it’s done, tap Step by Step Explanation under the grid: the grid and the current step stay on screen together while you follow the solution one logical move at a time (R = row, C = column, counted from the top-left).
Everyday Grids Sums Normal Answer, Mar 29, 2026
6×6 grid- 0/11Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 11 logical steps, no guessing.
- 1/11Yellow area must total 3 using 3, 6, 3, 5. The ways to make 3 are: 3 (some using different copies of the same number). None uses R6C3, R6C5, so remove them.
- 2/11Row 6 must total 17 using 1, 7, 3, 6. The only way to make 17 is 1 + 7 + 3 + 6. So keep R6C1, R6C2, R6C4, R6C6.
- 3/11Column 1 must total 12; the kept 1 = 1 so far, so the undecided numbers (3, 5, 4, 3, 9) must add up to 11. The only way to make 11 is 3 + 5 + 3. So keep R1C1, R2C1, R4C1; remove R3C1, R5C1.
- 4/11Row 4 must total 6; the kept 3 = 3 so far, so the undecided numbers (5, 9, 3, 1, 1) must add up to 3. The only way to make 3 is 3. So keep R4C4; remove R4C2, R4C3, R4C5, R4C6.
- 5/11Column 4 must total 18; the kept 3+3 = 6 so far, so the undecided numbers (5, 2, 3, 5) must add up to 12. The only way to make 12 is 5 + 2 + 5. So keep R1C4, R2C4, R5C4; remove R3C4.
- 6/11Row 1 must total 17; the kept 3+5 = 8 so far, so the undecided numbers (6, 2, 5, 1) must add up to 9. The only way to make 9 is 6 + 2 + 1. So keep R1C2, R1C3, R1C6; remove R1C5.
- 7/11Purple area must total 14; the kept 2 = 2 so far, so the undecided numbers (3, 6, 5, 4) must add up to 12. The only way to make 12 is 3 + 5 + 4. So keep R2C5, R3C5, R3C6; remove R2C6.
- 8/11Row 2 must total 17; the kept 5+2+3 = 10 so far, so the undecided numbers (4, 7) must add up to 7. The only way to make 7 is 7. So keep R2C3; remove R2C2.
- 9/11Row 3 must total 18; the kept 5+4 = 9 so far, so the undecided numbers (9, 4) must add up to 9. The only way to make 9 is 9. So keep R3C2; remove R3C3.
- 10/11Peach area must total 11; the kept 5+6 = 11 so far, so the undecided numbers (4, 7) must add up to 0. Nothing more is needed. Remove R5C5, R5C6.
- 11/11Row 5 must total 9; the kept 5 = 5 so far, so the undecided numbers (4, 3) must add up to 4. The only way to make 4 is 4. So keep R5C2; remove R5C3. ✅ Solved!
Sums Normal answer as text
Everyday Grids Sums Hard Answer, Mar 29, 2026
7×7 grid- 0/18Keep the numbers that add up to every row total (left), column total (top) and colour-area total (small tag). Tap Start to follow all 18 logical steps, no guessing.
- 1/18Brown area must total 15 using 8, 5, 4, 5, 2, 2. The ways to make 15 are: 8+5+2 (some using different copies of the same number). Every one uses R5C6, so keep it; none uses R6C6, so remove it.
- 2/18Row 6 must total 12 using 3, 5, 3, 9, 9, 5. The ways to make 12 are: 3+9 (some using different copies of the same number). None uses R6C2, R6C7, so remove them.
- 3/18Column 7 must total 18 using 9, 8, 3, 3, 5, 2. The ways to make 18 are: 8+3+5+2 (some using different copies of the same number). Every one uses R2C7, R5C7, R7C7, so keep them; none uses R1C7, so remove it.
- 4/18Brown area must total 15; the kept 8+5+2 = 15 so far, so the undecided numbers (2) must add up to 0. Nothing more is needed. Remove R7C6.
- 5/18Column 6 must total 17; the kept 8 = 8 so far, so the undecided numbers (7, 1, 5, 1) must add up to 9. The only way to make 9 is 7 + 1 + 1. So keep R1C6, R2C6, R4C6; remove R3C6.
- 6/18Row 3 must total 22 using 1, 4, 9, 5, 7, 3. The ways to make 22 are: 1+4+9+5+3, 1+9+5+7. Every one uses R3C1, R3C3, R3C4, so keep them.
- 7/18Yellow area must total 25; the kept 9 = 9 so far, so the undecided numbers (9, 9, 4, 3, 2) must add up to 16. The ways to make 16 are: 9+4+3 (some using different copies of the same number). Every one uses R4C3, R5C2, so keep them; none uses R5C3, so remove it.
- 8/18Row 1 must total 23; the kept 7 = 7 so far, so the undecided numbers (2, 9, 6, 5, 3) must add up to 16. The ways to make 16 are: 2+9+5, 2+6+5+3. Every one uses R1C1, R1C4, so keep them.
- 9/18Row 2 must total 26; the kept 1+8 = 9 so far, so the undecided numbers (7, 4, 9, 8, 5) must add up to 17. The ways to make 17 are: 4+8+5, 9+8. Every one uses R2C4, so keep it; none uses R2C1, so remove it.
- 10/18Column 4 must total 26; the kept 5+8+5 = 18 so far, so the undecided numbers (4, 1, 9, 7) must add up to 8. The only way to make 8 is 1 + 7. So keep R5C4, R7C4; remove R4C4, R6C4.
- 11/18Row 4 must total 25; the kept 4+1 = 5 so far, so the undecided numbers (8, 9, 7, 3) must add up to 20. The only way to make 20 is 8 + 9 + 3. So keep R4C1, R4C2, R4C7; remove R4C5.
- 12/18Column 1 must total 11; the kept 2+1+8 = 11 so far, so the undecided numbers (4, 3, 5) must add up to 0. Nothing more is needed. Remove R5C1, R6C1, R7C1.
- 13/18Row 7 must total 17; the kept 7+2 = 9 so far, so the undecided numbers (8, 3, 3) must add up to 8. The only way to make 8 is 8. So keep R7C2; remove R7C3, R7C5.
- 14/18Column 5 must total 27 using 3, 5, 7, 3, 9. The only way to make 27 is 3 + 5 + 7 + 3 + 9. So keep R1C5, R2C5, R3C5, R5C5, R6C5.
- 15/18Row 1 must total 23; the kept 2+5+3+7 = 17 so far, so the undecided numbers (9, 6) must add up to 6. The only way to make 6 is 6. So keep R1C3; remove R1C2.
- 16/18Row 2 must total 26; the kept 8+5+1+8 = 22 so far, so the undecided numbers (4, 9) must add up to 4. The only way to make 4 is 4. So keep R2C2; remove R2C3.
- 17/18Row 3 must total 22; the kept 1+9+5+7 = 22 so far, so the undecided numbers (4, 3) must add up to 0. Nothing more is needed. Remove R3C2, R3C7.
- 18/18Row 6 must total 12; the kept 9 = 9 so far, so the undecided numbers (3) must add up to 3. The only way to make 3 is 3. So keep R6C3. ✅ Solved!
Sums Hard answer as text
How to Solve Everyday Grids Sums: Quick Tips
- Compare each total with the numbers in its line: anything bigger than the remaining total can be removed.
- Small totals usually allow only one combination, start there.
- Colour-area totals and row/column totals must agree, so check them together.
- Once a line's total is reached, every other number in it is removed.